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A voltage source having an open circuit voltage of 100 V and internal resistance of 50 ohms is equivalent to a current source of:
  • a)
    2 A in parallel with 100 ohms
  • b)
    2 A in series with 50 ohms
  • c)
    0.5 A in parallel with 50 ohms
  • d)
    2 A in parallel with 50 ohms
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A voltage source having an open circuit voltage of 100 V and internal ...
A voltage source having an open circuit voltage of 100 V and internal resistance of 50 ohms can be represented as 100 V voltage source in series with a resistance of 50 ohms as shown in the below figure.

By source transformation, we can represent this circuit as a current source with resistance in parallel.
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Most Upvoted Answer
A voltage source having an open circuit voltage of 100 V and internal ...
Explanation:
To determine the equivalent current source, we need to find the current that would flow through a short circuit connected across the voltage source.

Given:
Open circuit voltage (Voc) = 100 V
Internal resistance (Rint) = 50 ohms

Step 1: Calculate the short circuit current (Isc)
When a short circuit is connected across the voltage source, the internal resistance is effectively bypassed, and the entire voltage is applied across the short circuit. Therefore, the current flowing through the short circuit is equal to the open circuit voltage divided by the internal resistance.

Isc = Voc / Rint
= 100 V / 50 ohms
= 2 A

Step 2: Determine the equivalent current source
The equivalent current source is determined by the short circuit current (Isc) and the internal resistance (Rint). In this case, the equivalent current source is given by the short circuit current in parallel with the internal resistance.

Equivalent current source = Isc || Rint
= 2 A || 50 ohms
= 2 A in parallel with 50 ohms

Therefore, the correct answer is option 'D': 2 A in parallel with 50 ohms.
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A voltage source having an open circuit voltage of 100 V and internal resistance of 50 ohms is equivalent to a current source of:a)2 A in parallel with 100 ohmsb)2 A in series with 50 ohmsc)0.5 A in parallel with 50 ohmsd)2 A in parallel with 50 ohmsCorrect answer is option 'D'. Can you explain this answer?
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