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The temperature profile at a particular location in a thermal boundary layer is prescribed by n expression of the form
t (y) = A- B y + C y 2
Where, A, B and Care constants. What is the value of heat transfer coefficient?
t (y) = A- B y + C y 2
Where, A, B and Care constants. What is the value of heat transfer coefficient?
- a)B k/ (t s – t infinity)
- b)2 B k/ (t s – t infinity)
- c)3 B k/ (t s – t infinity)
- d)4 B k/ (t s – t infinity)
Correct answer is option 'A'. Can you explain this answer?
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The temperature profile at a particular location in a thermal boundary...
h = – k/ (t s – t infinity) [d t/d y] y = 0 and (d t/d y) y = 0 = – B.
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The temperature profile at a particular location in a thermal boundary...
The heat transfer coefficient can be determined by considering the thermal boundary layer and using the temperature profile equation.
In the thermal boundary layer, the temperature gradient can be approximated as:
dT/dy = -B - 2C y
The heat transfer coefficient (h) is related to the temperature gradient as:
h = -k (dT/dy)
Substituting the temperature gradient equation into the heat transfer coefficient equation, we get:
h = -k (-B - 2C y)
Simplifying, we have:
h = B k + 2C k y
Therefore, the value of the heat transfer coefficient is Bk + 2Ck.
In the thermal boundary layer, the temperature gradient can be approximated as:
dT/dy = -B - 2C y
The heat transfer coefficient (h) is related to the temperature gradient as:
h = -k (dT/dy)
Substituting the temperature gradient equation into the heat transfer coefficient equation, we get:
h = -k (-B - 2C y)
Simplifying, we have:
h = B k + 2C k y
Therefore, the value of the heat transfer coefficient is Bk + 2Ck.
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