The sum of three numbers is 98. If the ratio of the first to second is...
**Given Information:**
- The sum of three numbers is 98.
- The ratio of the first number to the second number is 2:3.
- The ratio of the second number to the third number is 5:8.
**Let's solve the problem step by step:**
**Step 1:**
Let's assume the three numbers as follows:
- The first number = 2x
- The second number = 3x
- The third number = 8y
**Step 2:**
According to the given information, the sum of the three numbers is 98. Therefore, we can write the equation as:
2x + 3x + 8y = 98
**Step 3:**
Simplifying the equation, we get:
5x + 8y = 98
**Step 4:**
Now, we need to find the values of x and y in order to find the second number.
**Step 5:**
According to the given information, the ratio of the second number to the third number is 5:8. Therefore, we can write the equation as:
3x/8y = 5/8
**Step 6:**
Cross-multiplying the equation, we get:
24x = 40y
**Step 7:**
Simplifying the equation, we get:
3x = 5y
**Step 8:**
Now, we have two equations:
5x + 8y = 98
3x = 5y
**Step 9:**
Substituting the value of 3x from the second equation into the first equation, we get:
5(5y/3) + 8y = 98
25y/3 + 8y = 98
(25y + 24y)/3 = 98
49y/3 = 98
49y = 294
y = 294/49
y = 6
**Step 10:**
Substituting the value of y into the second equation, we get:
3x = 5(6)
3x = 30
x = 30/3
x = 10
**Step 11:**
Now, we can find the second number:
The second number = 3x = 3 * 10 = 30
Therefore, the correct answer is option **B) 30**.
The sum of three numbers is 98. If the ratio of the first to second is...
Let three nubers be x,y,z
x+y+z=98;
x:y = 2:3
=> x/y = 2/3
=> y = 3x/2
y:z = 5:8
=> y/z = 5/8
=> 3x/2z = 5/8
=> 12x= 5z
=> z = 12x/5
x+y+z = 98
substituting y and z values in above eq
x+3x/2+12x/5 = 98
=> (10x+15x+24x)/10= 98
=> 49x = 980
=> x = 20
substitute x value in y & z
y = 3x/2 = 30;
z = 12x/5 = 48;
x= 20; y = 30; z = 48;