Balanced Reaction
The balanced chemical equation provided is:
4NH₃ + 5O₂ → 4NO + 6H₂O
This indicates that 4 moles of ammonia react with 5 moles of oxygen to produce 4 moles of nitrogen monoxide (NO) and 6 moles of water (H₂O).
Reactants Used
When 1 mole of ammonia (NH₃) and 1 mole of oxygen (O₂) are reacted, we need to determine the limiting reactant based on the stoichiometry of the reaction.
Stoichiometric Ratios
- According to the balanced equation:
- 4 moles of NH₃ require 5 moles of O₂.
- From this, the ratio of NH₃ to O₂ is:
- 4 NH₃ : 5 O₂
- Which simplifies to 0.8 NH₃ : 1 O₂
Limiting Reactant Calculation
- Given that we have 1 mole of NH₃:
- Required O₂ = (5/4) × 1 mole NH₃ = 1.25 moles O₂
- Since only 1 mole of O₂ is available, O₂ is the limiting reactant.
Products Formed
- From the stoichiometry:
- 5 moles of O₂ produce 4 moles of NO.
- With 1 mole of O₂:
- NO produced = (4/5) × 1 mole O₂ = 0.8 moles NO
- Water produced = (6/5) × 1 mole O₂ = 1.2 moles H₂O
Conclusion
When 1 mole of NH₃ reacts with 1 mole of O₂, it will yield 0.8 moles of NO and 1.2 moles of H₂O, with O₂ being the limiting reactant.