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Renu's mother was three times as old as Renu 5 years ago. After 5 years, she will be twice as old as Renu. Renu's present age in years is
  • a)
    35
  • b)
    10
  • c)
    20
  • d)
    15
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Renu's mother was three times as old as Renu 5 years ago. After 5 ...
Given: 3(R - 5) = (M - 5)
and, 2(R + 5) = (M + 5)
∴ M = 35, R = 15
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Most Upvoted Answer
Renu's mother was three times as old as Renu 5 years ago. After 5 ...
Given information:
- Renu's mother was three times as old as Renu 5 years ago.
- After 5 years, Renu's mother will be twice as old as Renu.

Let's assume Renu's present age is 'x' years and her mother's present age is 'y' years.

Renu's age 5 years ago: x - 5
Renu's mother's age 5 years ago: y - 5

According to the first statement, Renu's mother was three times as old as Renu 5 years ago:
y - 5 = 3(x - 5)
y - 5 = 3x - 15
3x - y = 10 ...........(1)

According to the second statement, after 5 years, Renu's mother will be twice as old as Renu:
y + 5 = 2(x + 5)
y + 5 = 2x + 10
2x - y = -5 ...........(2)

We have a system of two equations (1) and (2) with two variables (x and y). We can solve these equations to find the values of x and y.

Solving equations (1) and (2) simultaneously, we get:
3x - y = 10 ...........(1)
2x - y = -5 ...........(2)

Subtracting equation (2) from equation (1), we get:
3x - 2x = 10 - (-5)
x = 15

Substituting the value of x in equation (2), we get:
2(15) - y = -5
30 - y = -5
y = 35

Therefore, Renu's present age is 15 years (option D).
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Renu's mother was three times as old as Renu 5 years ago. After 5 years, she will be twice as old as Renu. Renu's present age in years isa)35b)10c)20d)15Correct answer is option 'D'. Can you explain this answer?
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