Class 10 Exam > Class 10 Questions > An unbiased die is thrown once. The probabili...
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An unbiased die is thrown once. The probability of getting a prime number is
- a)1/3
- b)1/4
- c)1/2
- d)1/5
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
An unbiased die is thrown once. The probability of getting a prime num...
Number of possible outcomes = {2, 3, 5} = 3
Number of Total outcomes = 6
∴ Probability of getting a prime number = 3/6 = 1/2
Number of Total outcomes = 6
∴ Probability of getting a prime number = 3/6 = 1/2
Most Upvoted Answer
An unbiased die is thrown once. The probability of getting a prime num...
Understanding the problem:
We are given that an unbiased die is thrown once. We need to find the probability of getting a prime number.
Prime numbers:
Prime numbers are the positive integers greater than 1 that have no positive integer divisors other than 1 and itself. The first few prime numbers are 2, 3, 5, 7, 11, 13, and so on.
Calculating the probability:
To calculate the probability of getting a prime number when throwing an unbiased die, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Possible outcomes:
When throwing an unbiased die, the possible outcomes are the numbers from 1 to 6. So, there are 6 possible outcomes.
Favorable outcomes:
To determine the favorable outcomes, we need to identify the prime numbers from 1 to 6. The prime numbers in this range are 2, 3, and 5. So, there are 3 favorable outcomes.
Probability calculation:
The probability of an event occurring is given by the formula:
Probability = Number of favorable outcomes / Total number of outcomes
In this case, the probability of getting a prime number is:
Probability = 3 (favorable outcomes) / 6 (total outcomes) = 1/2
Therefore, the correct answer is option 'C' (1/2).
We are given that an unbiased die is thrown once. We need to find the probability of getting a prime number.
Prime numbers:
Prime numbers are the positive integers greater than 1 that have no positive integer divisors other than 1 and itself. The first few prime numbers are 2, 3, 5, 7, 11, 13, and so on.
Calculating the probability:
To calculate the probability of getting a prime number when throwing an unbiased die, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Possible outcomes:
When throwing an unbiased die, the possible outcomes are the numbers from 1 to 6. So, there are 6 possible outcomes.
Favorable outcomes:
To determine the favorable outcomes, we need to identify the prime numbers from 1 to 6. The prime numbers in this range are 2, 3, and 5. So, there are 3 favorable outcomes.
Probability calculation:
The probability of an event occurring is given by the formula:
Probability = Number of favorable outcomes / Total number of outcomes
In this case, the probability of getting a prime number is:
Probability = 3 (favorable outcomes) / 6 (total outcomes) = 1/2
Therefore, the correct answer is option 'C' (1/2).
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Community Answer
An unbiased die is thrown once. The probability of getting a prime num...
C is the correct answer
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An unbiased die is thrown once. The probability of getting a prime number isa)1/3b)1/4c)1/2d)1/5Correct answer is option 'C'. Can you explain this answer?
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