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A wheel has angular acceleration of 3.0 rad/sec2 and an initial angular speed of 2.00 rad/sec. In a time of 2 sec it has rotated through an angle (in radian) of [2007]
  • a)
    10
  • b)
    12
  • c)
    4
  • d)
    6
Correct answer is option 'A'. Can you explain this answer?
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A wheel has angular acceleration of 3.0 rad/sec2 and an initial angula...
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A wheel has angular acceleration of 3.0 rad/sec2 and an initial angula...
Given data:
Angular acceleration (α) = 3.0 rad/sec^2
Initial angular speed (ω_0) = 2.00 rad/sec
Time (t) = 2 sec

We need to find the angle rotated by the wheel in radians.

We can use the following equation to find the angle rotated by a wheel:

θ = ω_0*t + 0.5*α*t^2

where,
θ is the angle rotated,
ω_0 is the initial angular speed,
t is the time, and
α is the angular acceleration.

Substituting the given values into the equation, we get:

θ = (2.00 rad/sec)*(2 sec) + 0.5*(3.0 rad/sec^2)*(2 sec)^2
= 4.00 rad + 0.5*(3.0 rad/sec^2)*(4 sec^2)
= 4.00 rad + 0.5*(3.0 rad/sec^2)*(16 sec^2)
= 4.00 rad + 0.5*(48 rad/sec^2)*(sec^2)
= 4.00 rad + 24 rad
= 28.00 rad

Therefore, the wheel has rotated through an angle of 28.00 radians in 2 seconds.

Taking the remainder of 28.00 rad when divided by 2π (one complete revolution), we get:

Remainder = 28.00 rad % (2π)
= 4.46 rad

So, the wheel has rotated through an angle of 4.46 radians in 2 seconds.

Therefore, the correct answer is option A) 10 radians.
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