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A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s2)
- a)30 J
- b)40 J [2009]
- c)10 J
- d)20 J
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momen...
When the body is thrown upwards. its K.E is converted into P.E. The loss of energy due to air friction is the difference of K.E and P.E.
= 200 – 180 = 20 J
Most Upvoted Answer
A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momen...
To find the energy lost due to air friction, we can use the concept of work-energy theorem.
**Work-Energy Theorem:**
The work done on an object is equal to the change in its kinetic energy.
**Given:**
Mass of the body, m = 1 kg
Initial velocity, u = 20 m/s
Final velocity, v = 0 m/s (as it momentarily comes to rest)
Height, h = 18 m
Acceleration due to gravity, g = 10 m/s^2
**Step 1: Calculate the initial kinetic energy (K1)**
The initial kinetic energy (K1) of the body can be calculated using the formula:
K1 = (1/2) * m * u^2
Substituting the given values:
K1 = (1/2) * 1 * (20)^2
K1 = 200 J
**Step 2: Calculate the final potential energy (P2)**
The final potential energy (P2) of the body can be calculated using the formula:
P2 = m * g * h
Substituting the given values:
P2 = 1 * 10 * 18
P2 = 180 J
**Step 3: Calculate the energy lost due to air friction (E)**
According to the work-energy theorem, the work done on the body is equal to the change in its kinetic energy. In this case, the work done is negative as the body loses energy.
The work done (W) can be calculated using the formula:
W = K1 - P2
Substituting the calculated values:
W = 200 - 180
W = 20 J
Therefore, the energy lost due to air friction is 20 J.
Hence, the correct answer is option D) 20 J.
**Work-Energy Theorem:**
The work done on an object is equal to the change in its kinetic energy.
**Given:**
Mass of the body, m = 1 kg
Initial velocity, u = 20 m/s
Final velocity, v = 0 m/s (as it momentarily comes to rest)
Height, h = 18 m
Acceleration due to gravity, g = 10 m/s^2
**Step 1: Calculate the initial kinetic energy (K1)**
The initial kinetic energy (K1) of the body can be calculated using the formula:
K1 = (1/2) * m * u^2
Substituting the given values:
K1 = (1/2) * 1 * (20)^2
K1 = 200 J
**Step 2: Calculate the final potential energy (P2)**
The final potential energy (P2) of the body can be calculated using the formula:
P2 = m * g * h
Substituting the given values:
P2 = 1 * 10 * 18
P2 = 180 J
**Step 3: Calculate the energy lost due to air friction (E)**
According to the work-energy theorem, the work done on the body is equal to the change in its kinetic energy. In this case, the work done is negative as the body loses energy.
The work done (W) can be calculated using the formula:
W = K1 - P2
Substituting the calculated values:
W = 200 - 180
W = 20 J
Therefore, the energy lost due to air friction is 20 J.
Hence, the correct answer is option D) 20 J.
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A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s2)a)30 Jb)40 J [2009]c)10 Jd)20 JCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s2)a)30 Jb)40 J [2009]c)10 Jd)20 JCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s2)a)30 Jb)40 J [2009]c)10 Jd)20 JCorrect answer is option 'D'. Can you explain this answer?.
A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s2)a)30 Jb)40 J [2009]c)10 Jd)20 JCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s2)a)30 Jb)40 J [2009]c)10 Jd)20 JCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s2)a)30 Jb)40 J [2009]c)10 Jd)20 JCorrect answer is option 'D'. Can you explain this answer?.
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