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If radiant energy EB emitted by the black surface strikes the non-black surface. If non-black surface has absorptivity α, it will absorb how much radiations?
- a)αEB
- b)2 αEB
- c)3 αEB
- d)4 αEB
Correct answer is option 'A'. Can you explain this answer?
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If radiant energy EBemitted by the black surface strikes the non-black...
The remainder (1 – α) will be reflected back for full absorption at the black surface.
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If radiant energy EBemitted by the black surface strikes the non-black...
The amount of radiant energy absorbed by the non-black surface depends on its absorptivity, which is a measure of the surface's ability to absorb radiation. If the non-black surface has an absorptivity of 0.5, for example, it will absorb half of the radiant energy emitted by the black surface.
The amount of energy absorbed can be calculated using the following formula:
Eabsorbed = EB x α
where Eabsorbed is the amount of energy absorbed by the non-black surface, EB is the radiant energy emitted by the black surface, and α is the absorptivity of the non-black surface.
For example, if the black surface emits 100 units of radiant energy and the non-black surface has an absorptivity of 0.5, then the amount of energy absorbed by the non-black surface would be:
Eabsorbed = 100 x 0.5 = 50 units of energy.
The amount of energy absorbed can be calculated using the following formula:
Eabsorbed = EB x α
where Eabsorbed is the amount of energy absorbed by the non-black surface, EB is the radiant energy emitted by the black surface, and α is the absorptivity of the non-black surface.
For example, if the black surface emits 100 units of radiant energy and the non-black surface has an absorptivity of 0.5, then the amount of energy absorbed by the non-black surface would be:
Eabsorbed = 100 x 0.5 = 50 units of energy.
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