A square of side 7cmis inscribed in a circle. The area enclosed betwee...
Side of square = 7 cm
Area of square = (7)^2 =49 cm^ 2
Diagonal of square = Diameter of circle
Diagonal of square = 7root 2
Diameter of circle = 7 root 2
Radius of circle = 7root 2 / 2
Area of circle = 22/7 × 7root 2 × 7 root 2 = 77 cm ^2
So, The area enclosed between the circle and the square = 77 - 49= 28 cm^2
A square of side 7cmis inscribed in a circle. The area enclosed betwee...
To find the area enclosed between the circle and the square, we need to first calculate the area of the circle and the area of the square.
The area of a circle can be calculated using the formula A = πr^2, where A is the area and r is the radius. Since the square is inscribed in the circle, the side of the square is equal to the diameter of the circle. Therefore, the radius of the circle is half the length of the side of the square, which is 7/2 = 3.5 cm.
Calculating the area of the circle:
A = π(3.5)^2
A = π(12.25)
A ≈ 38.465 sq. cm
The area of a square can be calculated using the formula A = s^2, where A is the area and s is the length of a side. In this case, the side of the square is 7 cm.
Calculating the area of the square:
A = 7^2
A = 49 sq. cm
Now, we need to find the difference between the area of the circle and the area of the square, which represents the area enclosed between them.
Area enclosed between the circle and the square:
38.465 - 49 ≈ -10.535 sq. cm
However, since area cannot be negative, we take the absolute value of the difference.
Absolute value of the area enclosed:
|-10.535| ≈ 10.535 sq. cm
Since none of the given options match the calculated area, it appears that there may be an error in the given question or options. Please double-check the question and options to ensure accuracy.