NEET Exam > NEET Questions > A stone tied to the end of a string of 1 m lo...
Start Learning for Free
A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]
- a)π2 ms–2 and direction along the radius towards the centre
- b)π2 ms–2 and direction along the radius away from the centre
- c)π2 ms–2 and direction along the tangent to the circle
- d)π2/4 ms–2 and direction along the radius towards the centre
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A stone tied to the end of a string of 1 m long is whirled in a horizo...
First, we need to find the angular velocity (ω) of the stone:
Number of revolutions = 22
Time taken = 44 seconds
Therefore, frequency (f) = number of revolutions / time taken = 22/44 = 0.5 Hz
Angular velocity (ω) = 2πf = 2π(0.5) = π rad/s
Next, we can use the formula for centripetal acceleration (ac) to find the magnitude of acceleration:
ac = ω2r
where r is the radius of the circle (1 m).
ac = (π)2(1) = 9.87 m/s2
The direction of acceleration is towards the center of the circle (i.e. radially inward).
Therefore, the magnitude of acceleration of the stone is 9.87 m/s2 and the direction is radially inward.
Number of revolutions = 22
Time taken = 44 seconds
Therefore, frequency (f) = number of revolutions / time taken = 22/44 = 0.5 Hz
Angular velocity (ω) = 2πf = 2π(0.5) = π rad/s
Next, we can use the formula for centripetal acceleration (ac) to find the magnitude of acceleration:
ac = ω2r
where r is the radius of the circle (1 m).
ac = (π)2(1) = 9.87 m/s2
The direction of acceleration is towards the center of the circle (i.e. radially inward).
Therefore, the magnitude of acceleration of the stone is 9.87 m/s2 and the direction is radially inward.
Free Test
FREE
| Start Free Test |
Community Answer
A stone tied to the end of a string of 1 m long is whirled in a horizo...
Freq of Rev = No.of Rev /Time= 22/44= 0.5
Now angular frequency w = 2πf = 2×π×0.5 = π
since the magnitude of velocity is constant, there is no tangential acceleration. so net acceleration= racial acceleration=( w^2 )× R = π^2 ms-2. and since there is only this radial acceleration, it's direction will be radially inwards towards the centre. optn A
Now angular frequency w = 2πf = 2×π×0.5 = π
since the magnitude of velocity is constant, there is no tangential acceleration. so net acceleration= racial acceleration=( w^2 )× R = π^2 ms-2. and since there is only this radial acceleration, it's direction will be radially inwards towards the centre. optn A
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer?
Question Description
A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer?.
A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A stone tied to the end of a string of 1 m long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolutions in 44 seconds, what is the magnitude and direction of acceleration of the stone? [2005]a)π2 ms–2 and direction along the radius towards the centreb)π2 ms–2 and direction along the radius away from the centrec)π2 ms–2 and direction along the tangent to the circled)π2/4 ms–2 and direction along the radius towards the centreCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup