**Understanding the Problem:**

We are given the following information:

Resistance of the electric bulb, R = 80 ohms
Voltage of the main supply, V = 220 volts

We need to find the power of the current.

**Using Ohm's Law:**

Ohm's law states that the current flowing through a conductor is directly proportional to the voltage across the conductor and inversely proportional to the resistance of the conductor.

Mathematically, Ohm's Law can be expressed as:

V = I * R

Where:
V is the voltage across the conductor,
I is the current flowing through the conductor,
R is the resistance of the conductor.

**Calculating the Current:**

To calculate the current flowing through the electric bulb, we can rearrange Ohm's Law equation as:

I = V / R

Substituting the given values:
V = 220 volts
R = 80 ohms

I = 220 / 80
I ≈ 2.75 amperes

Therefore, the current flowing through the electric bulb is approximately 2.75 amperes.

**Calculating Power:**

The power (P) can be calculated using the formula:

P = V * I

Substituting the given values:
V = 220 volts
I ≈ 2.75 amperes

P = 220 * 2.75
P ≈ 605 watts

Therefore, the power of the current flowing through the electric bulb is approximately 605 watts.

Given-
R=80 ohms
V=220v
P=V×I

I=V/R

=220/80
now,
p= 220× 220/80..

p=220×2.75
p =605W ans..
I= 2.75A...