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Of the radiant energy 350W/m2 incident upon a surface 250W/m2 is absorbed, 60W/m2 is reflected and the remainder is transmitted through the surface. Workout the value for reflectivity for the surface material
  • a)
    0.181
  • b)
    0.171
  • c)
    0.161
  • d)
    0.151
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Of the radiant energy 350W/m2incident upon a surface 250W/m2is absorbe...
Reflectivity = fraction of total energy reflected by the body = 60/350 = 0.171.
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Of the radiant energy 350W/m2incident upon a surface 250W/m2is absorbe...

Calculation of Reflectivity:

Reflectivity (ρ) is the ratio of the reflected radiant energy to the incident radiant energy. It can be calculated using the formula:
\[ ρ = \frac{Reflected\: Energy}{Incident\: Energy} \]

Given data:
- Incident radiant energy (I) = 350 W/m2
- Absorbed radiant energy (A) = 250 W/m2
- Reflected radiant energy (R) = 60 W/m2

Calculations:
1. Calculate the total transmitted radiant energy:
\[ Total\: Transmitted\: Energy = Incident\: Energy - Absorbed\: Energy - Reflected\: Energy \]
\[ Total\: Transmitted\: Energy = 350 - 250 - 60 = 40 W/m2 \]

2. Calculate the reflectivity:
\[ Reflectivity = \frac{Reflected\: Energy}{Incident\: Energy} = \frac{60}{350} = 0.171 \]

Therefore, the reflectivity for the surface material is 0.171, which matches option B.
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Of the radiant energy 350W/m2incident upon a surface 250W/m2is absorbed, 60W/m2is reflected and the remainder is transmitted through the surface. Workout the value for reflectivity for the surface materiala)0.181b)0.171c)0.161d)0.151Correct answer is option 'B'. Can you explain this answer?
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