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Of the radiant energy 350W/m2 incident upon a surface 250W/m2 is absorbed, 60W/m2 is reflected and the remainder is transmitted through the surface. Workout the value for reflectivity for the surface material

  • a)
    0.113

  • b)
    0.114

  • c)
    0.171

  • d)
    0.116

Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Of the radiant energy 350W/m2incident upon a surface 250W/m2is absorbe...
Reflectivity = fraction of total energy reflected by the body = 60/350 = 0.171.
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Most Upvoted Answer
Of the radiant energy 350W/m2incident upon a surface 250W/m2is absorbe...
Given: Incident radiant energy = 350 W/m2
Absorbed radiant energy = 250 W/m2
Reflected radiant energy = 60 W/m2

We know that the sum of reflected, absorbed and transmitted radiant energy should be equal to the incident radiant energy. Therefore,

Reflected + Absorbed + Transmitted = Incident
60 + 250 + Transmitted = 350
Transmitted = 40 W/m2

Now, we can calculate the reflectivity using the formula:

Reflectivity = Reflected / Incident
Reflectivity = 60 / 350
Reflectivity = 0.171

Therefore, the correct answer is option C, 0.171.
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Of the radiant energy 350W/m2incident upon a surface 250W/m2is absorbed, 60W/m2is reflected and the remainder is transmitted through the surface. Workout the value for reflectivity for the surface materiala)0.113b)0.114c)0.171d)0.116Correct answer is option 'C'. Can you explain this answer?
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