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The degree of freedom of a molecule of a triatomic ga s is[1999]
  • a)
    2
  • b)
    4
  • c)
    6
  • d)
    8
Correct answer is option 'C'. Can you explain this answer?
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The degree of freedom of a molecule of a triatomic ga s is[1999]a)2b)4...
No. of degree of freedom = 3 K – N where K is no. of atom and N is the number of relations between atoms. For triatomic gas, K = 3, N = 3C2 = 3
No. of degree of freedom = 3 (3) – 3 = 6
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