NEET Exam > NEET Questions > The equation of state for 5 g of oxygen at a ...
Start Learning for Free
The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]
- a)PV = (5/16) RT
- b)PV = (5/32) RT
- c)PV = 5 RT
- d)PV = (5/2) RT where R is the gas constant.
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The equation of state for 5 g of oxygen at a pressure P and temperatur...
[∵ PV = nRT]Most Upvoted Answer
The equation of state for 5 g of oxygen at a pressure P and temperatur...
Explanation:
The ideal gas law equation is given by: PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
In this question, we have 5 g of oxygen. To find the number of moles, we need to use the molar mass of oxygen.
The molar mass of oxygen (O₂) is 32 g/mol. Therefore, the number of moles of oxygen is given by:
n = mass/molar mass = 5 g/32 g/mol = 0.15625 mol
Now, we can substitute the values in the ideal gas law equation:
PV = nRT
P * V = (0.15625 mol) * R * T
To eliminate the need for the gas constant, we can rearrange the equation as follows:
PV = (0.15625 mol) * R * T
Now, we need to find the value of (0.15625 mol) * R. Let's call it 'k':
k = (0.15625 mol) * R
Therefore, the equation becomes:
PV = k * T
Now, we need to find the value of k. To do that, let's consider the ideal gas law equation for 1 mol of any gas:
PV = RT
Since we know that 1 mol of any gas at STP (standard temperature and pressure) occupies a volume of 22.4 L, we can substitute the values:
(1 mol) * (22.4 L) = R * (273 K)
Simplifying, we find:
R = (1 mol) * (22.4 L) / (273 K)
R = 0.0821 L mol⁻¹ K⁻¹ (approximately)
Substituting this value in the equation for k:
k = (0.15625 mol) * (0.0821 L mol⁻¹ K⁻¹)
k = 0.0128 L K⁻¹
Finally, substituting the value of k in the equation PV = k * T:
PV = (0.0128 L K⁻¹) * T
Simplifying further, we get:
PV = (5/32) * RT
Therefore, the correct equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, is PV = (5/32) RT. Hence, option B is the correct answer.
The ideal gas law equation is given by: PV = nRT
Where:
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
In this question, we have 5 g of oxygen. To find the number of moles, we need to use the molar mass of oxygen.
The molar mass of oxygen (O₂) is 32 g/mol. Therefore, the number of moles of oxygen is given by:
n = mass/molar mass = 5 g/32 g/mol = 0.15625 mol
Now, we can substitute the values in the ideal gas law equation:
PV = nRT
P * V = (0.15625 mol) * R * T
To eliminate the need for the gas constant, we can rearrange the equation as follows:
PV = (0.15625 mol) * R * T
Now, we need to find the value of (0.15625 mol) * R. Let's call it 'k':
k = (0.15625 mol) * R
Therefore, the equation becomes:
PV = k * T
Now, we need to find the value of k. To do that, let's consider the ideal gas law equation for 1 mol of any gas:
PV = RT
Since we know that 1 mol of any gas at STP (standard temperature and pressure) occupies a volume of 22.4 L, we can substitute the values:
(1 mol) * (22.4 L) = R * (273 K)
Simplifying, we find:
R = (1 mol) * (22.4 L) / (273 K)
R = 0.0821 L mol⁻¹ K⁻¹ (approximately)
Substituting this value in the equation for k:
k = (0.15625 mol) * (0.0821 L mol⁻¹ K⁻¹)
k = 0.0128 L K⁻¹
Finally, substituting the value of k in the equation PV = k * T:
PV = (0.0128 L K⁻¹) * T
Simplifying further, we get:
PV = (5/32) * RT
Therefore, the correct equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, is PV = (5/32) RT. Hence, option B is the correct answer.
Free Test
FREE
| Start Free Test |
Community Answer
The equation of state for 5 g of oxygen at a pressure P and temperatur...
PV=nRT
PV=(m/M)RT
PV=(5/32)RT (O mass is given at question is 5g
and molar mass of O is 32 )
Thus option B is correct.
PV=(m/M)RT
PV=(5/32)RT (O mass is given at question is 5g
and molar mass of O is 32 )
Thus option B is correct.
|
Explore Courses for NEET exam
|
|
Top Courses for NEETView all
Question Description
The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer?.
The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer?.
Solutions for The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be [2004]a)PV = (5/16) RTb)PV = (5/32) RTc)PV = 5 RTd)PV = (5/2) RT where R is the gas constant.Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup