NEET Exam > NEET Questions > Two metal rods 1 and 2 of same lengths have s...
Start Learning for Free
Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]
- a)K1A1 = K2A2
- b)K1A1 = 4K2A2
- c)K1A1 = 2K2A2
- d)4K1A1 = K2A2
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Two metal rods 1 and 2 of same lengths have same temperature differenc...
Q1 = 4Q2 (Given)
Most Upvoted Answer
Two metal rods 1 and 2 of same lengths have same temperature differenc...
**Given Information:**
- Two metal rods, 1 and 2, have the same length and the same temperature difference between their ends.
- The thermal conductivities of the rods are represented as K1 and K2.
- The cross-sectional areas of the rods are represented as A1 and A2.
- The rate of heat conduction in rod 1 is four times that in rod 2.
**To Find:**
The relationship between the thermal conductivities and cross-sectional areas of the rods.
**Explanation:**
Let's assume the rate of heat conduction in rod 1 is Q1 and in rod 2 is Q2.
According to Fourier's Law of Heat Conduction, the rate of heat conduction is given by:
Q = (k * A * ΔT) / L,
where Q is the rate of heat conduction, k is the thermal conductivity, A is the cross-sectional area, ΔT is the temperature difference, and L is the length of the rod.
**Step 1:**
Using the given information, we can write the equations for the rates of heat conduction in rod 1 and rod 2 as follows:
Q1 = (K1 * A1 * ΔT) / L,
Q2 = (K2 * A2 * ΔT) / L.
**Step 2:**
Given that the rate of heat conduction in rod 1 is four times that in rod 2, we can write the equation:
Q1 = 4 * Q2.
**Step 3:**
Substituting the expressions for Q1 and Q2 from Step 1 into the equation from Step 2, we get:
(K1 * A1 * ΔT) / L = 4 * (K2 * A2 * ΔT) / L.
**Step 4:**
Canceling out the common terms (ΔT and L) from both sides of the equation, we get:
K1 * A1 = 4 * K2 * A2.
**Step 5:**
Rearranging the equation, we obtain:
K1 * A1 = 4 * K2 * A2.
Therefore, the correct answer is option b) K1A1 = 4K2A2, which shows the relationship between the thermal conductivities and cross-sectional areas of the rods.
- Two metal rods, 1 and 2, have the same length and the same temperature difference between their ends.
- The thermal conductivities of the rods are represented as K1 and K2.
- The cross-sectional areas of the rods are represented as A1 and A2.
- The rate of heat conduction in rod 1 is four times that in rod 2.
**To Find:**
The relationship between the thermal conductivities and cross-sectional areas of the rods.
**Explanation:**
Let's assume the rate of heat conduction in rod 1 is Q1 and in rod 2 is Q2.
According to Fourier's Law of Heat Conduction, the rate of heat conduction is given by:
Q = (k * A * ΔT) / L,
where Q is the rate of heat conduction, k is the thermal conductivity, A is the cross-sectional area, ΔT is the temperature difference, and L is the length of the rod.
**Step 1:**
Using the given information, we can write the equations for the rates of heat conduction in rod 1 and rod 2 as follows:
Q1 = (K1 * A1 * ΔT) / L,
Q2 = (K2 * A2 * ΔT) / L.
**Step 2:**
Given that the rate of heat conduction in rod 1 is four times that in rod 2, we can write the equation:
Q1 = 4 * Q2.
**Step 3:**
Substituting the expressions for Q1 and Q2 from Step 1 into the equation from Step 2, we get:
(K1 * A1 * ΔT) / L = 4 * (K2 * A2 * ΔT) / L.
**Step 4:**
Canceling out the common terms (ΔT and L) from both sides of the equation, we get:
K1 * A1 = 4 * K2 * A2.
**Step 5:**
Rearranging the equation, we obtain:
K1 * A1 = 4 * K2 * A2.
Therefore, the correct answer is option b) K1A1 = 4K2A2, which shows the relationship between the thermal conductivities and cross-sectional areas of the rods.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer?
Question Description
Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer?.
Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer?.
Solutions for Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Two metal rods 1 and 2 of same lengths have same temperature difference between their ends.Their thermal conductivities are K1 and K2 and cross sectional areas A1 and A2, respectively. If the rate of heat conduction in rod 1 is four times that in rod 2, then [NEET Kar. 2013]a)K1A1 = K2A2b)K1A1 = 4K2A2c)K1A1 = 2K2A2d)4K1A1 = K2A2Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup