An electric kettle takes 4A current at 220 V. How much time will it ta...
Heat required to raise the temperature of 1kg water from 20°C to 100°C is given by Q = msΔθ = (1× 4200 × 80) J
Power of kettle (P) = VI = (220 × 4)W
∴ Time taken =

= 381.81 sec = 6.36 min
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An electric kettle takes 4A current at 220 V. How much time will it ta...
An electric kettle takes 4A current at 220 V. How much time will it ta...
To calculate the time it takes to boil the water, we need to know the specific heat capacity of water and the rate at which the kettle transfers heat to the water.
The specific heat capacity of water is approximately 4.18 Joules per gram per degree Celsius (J/g°C).
The formula to calculate the amount of heat required to raise the temperature of a substance is:
Q = m * c * ΔT
Where:
Q is the amount of heat (in Joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in J/g°C)
ΔT is the change in temperature (in °C)
In this case, we have 1 kg of water, which is equal to 1000 grams. The initial temperature is 20°C, and we want to raise it to the boiling point, which is 100°C. So, ΔT = 100 - 20 = 80°C.
Using the formula, we can calculate the amount of heat required:
Q = 1000 g * 4.18 J/g°C * 80°C
Q = 334,400 J
Now, let's calculate the time it takes to transfer this amount of heat to the water using the power equation:
Power = Work / Time
The power of the electric kettle is given as 4A * 220V = 880W (watts).
We know that Power = Work / Time, and Work = Q (the amount of heat required).
So, Time = Work / Power
Time = 334,400 J / 880 W
Time ≈ 380 seconds
Therefore, it will take approximately 380 seconds (or 6 minutes and 20 seconds) to boil 1 kg of water starting from a temperature of 20°C using an electric kettle that takes 4A current at 220V.