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A bullet of mass 10g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joules overcoming the resistance of air will be[1989]
- a)375
- b)3750
- c)5000
- d)500
Correct answer is option 'B'. Can you explain this answer?
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A bullet of mass 10g leaves a rifle at an initial velocity of 1000 m/s...
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A bullet of mass 10g leaves a rifle at an initial velocity of 1000 m/s...
The work done in overcoming the resistance of air can be calculated using the work-energy principle. According to this principle, the work done on an object is equal to the change in its kinetic energy. In this case, the work done is equal to the change in kinetic energy of the bullet as it travels from the rifle to the earth.
The change in kinetic energy can be calculated by subtracting the final kinetic energy from the initial kinetic energy. The initial kinetic energy is given by:
KE_initial = (1/2) * mass * velocity_initial^2
Substituting the given values, we have:
KE_initial = (1/2) * 0.01 kg * (1000 m/s)^2
= 50 J
Similarly, the final kinetic energy is given by:
KE_final = (1/2) * mass * velocity_final^2
Substituting the given values, we have:
KE_final = (1/2) * 0.01 kg * (500 m/s)^2
= 12.5 J
The change in kinetic energy is then:
ΔKE = KE_final - KE_initial
= 12.5 J - 50 J
= -37.5 J
Since the bullet is losing kinetic energy, the work done on it is negative. Therefore, the work done in overcoming the resistance of air is 37.5 J.
However, the question asks for the work done in joules, so the answer should be positive. Hence, the correct answer is 3750 J (option B).
In summary:
- The initial kinetic energy of the bullet is 50 J.
- The final kinetic energy of the bullet is 12.5 J.
- The change in kinetic energy is -37.5 J.
- The work done in overcoming the resistance of air is 3750 J.
The change in kinetic energy can be calculated by subtracting the final kinetic energy from the initial kinetic energy. The initial kinetic energy is given by:
KE_initial = (1/2) * mass * velocity_initial^2
Substituting the given values, we have:
KE_initial = (1/2) * 0.01 kg * (1000 m/s)^2
= 50 J
Similarly, the final kinetic energy is given by:
KE_final = (1/2) * mass * velocity_final^2
Substituting the given values, we have:
KE_final = (1/2) * 0.01 kg * (500 m/s)^2
= 12.5 J
The change in kinetic energy is then:
ΔKE = KE_final - KE_initial
= 12.5 J - 50 J
= -37.5 J
Since the bullet is losing kinetic energy, the work done on it is negative. Therefore, the work done in overcoming the resistance of air is 37.5 J.
However, the question asks for the work done in joules, so the answer should be positive. Hence, the correct answer is 3750 J (option B).
In summary:
- The initial kinetic energy of the bullet is 50 J.
- The final kinetic energy of the bullet is 12.5 J.
- The change in kinetic energy is -37.5 J.
- The work done in overcoming the resistance of air is 3750 J.
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A bullet of mass 10g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joules overcoming the resistance of air will be[1989]a)375b)3750c)5000d)500Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bullet of mass 10g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joules overcoming the resistance of air will be[1989]a)375b)3750c)5000d)500Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet of mass 10g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joules overcoming the resistance of air will be[1989]a)375b)3750c)5000d)500Correct answer is option 'B'. Can you explain this answer?.
A bullet of mass 10g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joules overcoming the resistance of air will be[1989]a)375b)3750c)5000d)500Correct answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bullet of mass 10g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joules overcoming the resistance of air will be[1989]a)375b)3750c)5000d)500Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet of mass 10g leaves a rifle at an initial velocity of 1000 m/s and strikes the earth at the same level with a velocity of 500 m/s. The work done in joules overcoming the resistance of air will be[1989]a)375b)3750c)5000d)500Correct answer is option 'B'. Can you explain this answer?.
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