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A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope ? (g = 10 m/s2) [2003]
- a)2.5 m/s2
- b)5 m/s2
- c)10 m/s2
- d)25 m/s2
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A monkey of mass 20 kg is holding a vertical rope. The rope will not b...
T = Tension caused in string by monkey
= m (g + a)
= m (g + a)
Most Upvoted Answer
A monkey of mass 20 kg is holding a vertical rope. The rope will not b...
Given:
Mass of monkey, m1 = 20 kg
Maximum mass that rope can hold, m2 = 25 kg
Acceleration, a = ?
Acceleration due to gravity, g = 10 m/s^2
To find: Maximum acceleration with which the monkey can climb up along the rope
Assumption:
The monkey climbs up with a constant acceleration 'a' and the rope remains vertical during the climb.
Explanation:
The tension in the rope while climbing is given as T = (m1 + m2)g
If the monkey climbs up with an acceleration 'a', then the tension in the rope will be T = (m1 + m2)(g + a)
As per the given condition, the rope will break if the tension exceeds (m2)g.
Therefore, (m1 + m2)(g + a) ≤ (m2)g
Simplifying the above equation, we get:
a ≤ g(m2 - m1)/m1
Substituting the values, we get:
a ≤ 10(25 - 20)/20
a ≤ 2.5 m/s^2
Therefore, the maximum acceleration with which the monkey can climb up along the rope is 2.5 m/s^2.
Answer: (a) 2.5 m/s^2
Mass of monkey, m1 = 20 kg
Maximum mass that rope can hold, m2 = 25 kg
Acceleration, a = ?
Acceleration due to gravity, g = 10 m/s^2
To find: Maximum acceleration with which the monkey can climb up along the rope
Assumption:
The monkey climbs up with a constant acceleration 'a' and the rope remains vertical during the climb.
Explanation:
The tension in the rope while climbing is given as T = (m1 + m2)g
If the monkey climbs up with an acceleration 'a', then the tension in the rope will be T = (m1 + m2)(g + a)
As per the given condition, the rope will break if the tension exceeds (m2)g.
Therefore, (m1 + m2)(g + a) ≤ (m2)g
Simplifying the above equation, we get:
a ≤ g(m2 - m1)/m1
Substituting the values, we get:
a ≤ 10(25 - 20)/20
a ≤ 2.5 m/s^2
Therefore, the maximum acceleration with which the monkey can climb up along the rope is 2.5 m/s^2.
Answer: (a) 2.5 m/s^2
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A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope ? (g = 10 m/s2) [2003]a)2.5 m/s2b)5 m/s2c)10 m/s2d)25 m/s2Correct answer is option 'A'. Can you explain this answer?
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A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope ? (g = 10 m/s2) [2003]a)2.5 m/s2b)5 m/s2c)10 m/s2d)25 m/s2Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope ? (g = 10 m/s2) [2003]a)2.5 m/s2b)5 m/s2c)10 m/s2d)25 m/s2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A monkey of mass 20 kg is holding a vertical rope. The rope will not break when a mass of 25 kg is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration with which the monkey can climb up along the rope ? (g = 10 m/s2) [2003]a)2.5 m/s2b)5 m/s2c)10 m/s2d)25 m/s2Correct answer is option 'A'. Can you explain this answer?.
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