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If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]
- a)0.55 kg/sec
- b)0.75 kg/sec
- c)1.15 kg/sec
- d)2.25 kg/sec
Correct answer is option 'C'. Can you explain this answer?
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If the force on a rocket moving with a velocity of 300 m/sec is 345 N,...
Velocity of the rocket (u) = 300 m/s and force (F) = 345N. Rate of combustion of fuel
Most Upvoted Answer
If the force on a rocket moving with a velocity of 300 m/sec is 345 N,...
To solve this problem, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the force acting on the rocket is 345 N and its velocity is 300 m/s. We need to find the rate of combustion of the fuel, which is the mass of the fuel burned per second.
Let's break down the problem into steps:
1. Identify the given values:
- Force (F) = 345 N
- Velocity (v) = 300 m/s
2. Determine the acceleration of the rocket:
- Since the rocket is moving with a constant velocity, its acceleration is zero.
- This means that the net force acting on the rocket is also zero (according to Newton's second law).
3. Calculate the mass of the rocket:
- Since the net force is zero, the force due to combustion of the fuel is balanced by an equal and opposite force.
- This opposing force is the force of air resistance.
- Therefore, the force due to combustion of the fuel is equal in magnitude to the force of air resistance.
- From the given information, we know that the force due to combustion of the fuel is 345 N.
- So, the force of air resistance is also 345 N.
- The force of air resistance can be expressed as the product of the drag coefficient, air density, velocity squared, and the reference area of the rocket.
- However, since we don't have information about the drag coefficient, air density, or reference area, we cannot directly calculate the mass of the rocket.
- Therefore, we assume that the mass of the rocket remains constant throughout the combustion of the fuel.
4. Calculate the rate of combustion of the fuel:
- The rate of combustion of the fuel is the mass of the fuel burned per second.
- Since the mass of the rocket remains constant, the rate of combustion of the fuel is equal to the rate of change of momentum of the rocket.
- Momentum (p) is defined as the product of mass and velocity (p = mv).
- Therefore, the rate of change of momentum is given by the formula: Δp/Δt = mΔv/Δt = m(a)
- Since the acceleration (a) is zero, the rate of change of momentum is also zero.
- Hence, the rate of combustion of the fuel is zero.
Therefore, the given options are incorrect and the correct answer is that the rate of combustion of the fuel is zero.
Let's break down the problem into steps:
1. Identify the given values:
- Force (F) = 345 N
- Velocity (v) = 300 m/s
2. Determine the acceleration of the rocket:
- Since the rocket is moving with a constant velocity, its acceleration is zero.
- This means that the net force acting on the rocket is also zero (according to Newton's second law).
3. Calculate the mass of the rocket:
- Since the net force is zero, the force due to combustion of the fuel is balanced by an equal and opposite force.
- This opposing force is the force of air resistance.
- Therefore, the force due to combustion of the fuel is equal in magnitude to the force of air resistance.
- From the given information, we know that the force due to combustion of the fuel is 345 N.
- So, the force of air resistance is also 345 N.
- The force of air resistance can be expressed as the product of the drag coefficient, air density, velocity squared, and the reference area of the rocket.
- However, since we don't have information about the drag coefficient, air density, or reference area, we cannot directly calculate the mass of the rocket.
- Therefore, we assume that the mass of the rocket remains constant throughout the combustion of the fuel.
4. Calculate the rate of combustion of the fuel:
- The rate of combustion of the fuel is the mass of the fuel burned per second.
- Since the mass of the rocket remains constant, the rate of combustion of the fuel is equal to the rate of change of momentum of the rocket.
- Momentum (p) is defined as the product of mass and velocity (p = mv).
- Therefore, the rate of change of momentum is given by the formula: Δp/Δt = mΔv/Δt = m(a)
- Since the acceleration (a) is zero, the rate of change of momentum is also zero.
- Hence, the rate of combustion of the fuel is zero.
Therefore, the given options are incorrect and the correct answer is that the rate of combustion of the fuel is zero.
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If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]a)0.55 kg/secb)0.75 kg/secc)1.15 kg/secd)2.25 kg/secCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]a)0.55 kg/secb)0.75 kg/secc)1.15 kg/secd)2.25 kg/secCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]a)0.55 kg/secb)0.75 kg/secc)1.15 kg/secd)2.25 kg/secCorrect answer is option 'C'. Can you explain this answer?.
If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]a)0.55 kg/secb)0.75 kg/secc)1.15 kg/secd)2.25 kg/secCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]a)0.55 kg/secb)0.75 kg/secc)1.15 kg/secd)2.25 kg/secCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]a)0.55 kg/secb)0.75 kg/secc)1.15 kg/secd)2.25 kg/secCorrect answer is option 'C'. Can you explain this answer?.
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If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]a)0.55 kg/secb)0.75 kg/secc)1.15 kg/secd)2.25 kg/secCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]a)0.55 kg/secb)0.75 kg/secc)1.15 kg/secd)2.25 kg/secCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of If the force on a rocket moving with a velocity of 300 m/sec is 345 N, then the rate of combustion of the fuel, is [1995]a)0.55 kg/secb)0.75 kg/secc)1.15 kg/secd)2.25 kg/secCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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