How many grams of Naoh will be required to neutralize 12.2 grams of be...
Explanation:
What is a Neutralization Reaction?
Neutralization reaction is a type of chemical reaction in which an acid and a base react to form salt and water by exchanging their ions in order to neutralize each other.
How to Calculate the Amount of NaOH Required to Neutralize Benzoic Acid?
The balanced chemical equation for the reaction between benzoic acid and sodium hydroxide is:
C6H5COOH + NaOH → C6H5COONa + H2O
From the equation, we can see that:
- 1 mole of benzoic acid reacts with 1 mole of sodium hydroxide
- The molar mass of benzoic acid is 122.12 g/mol
- The molar mass of sodium hydroxide is 40.00 g/mol
Using the given mass of benzoic acid, we can calculate the number of moles of benzoic acid:
Number of moles of benzoic acid = Mass of benzoic acid / Molar mass of benzoic acid
Number of moles of benzoic acid = 12.2 g / 122.12 g/mol
Number of moles of benzoic acid = 0.0999 mol
Since 1 mole of benzoic acid reacts with 1 mole of sodium hydroxide, we can say that:
Number of moles of sodium hydroxide = Number of moles of benzoic acid
Number of moles of sodium hydroxide = 0.0999 mol
Finally, we can calculate the mass of sodium hydroxide required:
Mass of sodium hydroxide = Number of moles of sodium hydroxide × Molar mass of sodium hydroxide
Mass of sodium hydroxide = 0.0999 mol × 40.00 g/mol
Mass of sodium hydroxide = 3.996 g
Answer:
Therefore, the mass of sodium hydroxide required to neutralize 12.2 grams of benzoic acid is 3.996 g.