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The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at an instant when the first drop touches the ground. How far above the ground is the second drop at that instant ? (Take g = 10 m/s2)[1995]
- a)1.25 m
- b)2.50 m
- c)3.75 m
- d)5.00 m
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The water drops fall at regular intervals from a tap 5 m above the gro...
Height of tap = 5m and (g) = 10 m/sec2.
For the first drop, 5 =
For the first drop, 5 =
= 5t2 or t2 = 1 or t = 1 sec.It means that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.
Distance covered by the second drop in 0.5 sec
= 1.25 m.
Therefore, distance of the second drop above the ground = 5 – 1.25 = 3.75 m.
Therefore, distance of the second drop above the ground = 5 – 1.25 = 3.75 m.
Most Upvoted Answer
The water drops fall at regular intervals from a tap 5 m above the gro...
Given: height of the tap, h = 5 m, acceleration due to gravity, g = 10 m/s².
To find: height of the second drop at the instant when the first drop touches the ground.
Solution:
Let the time taken by each drop to reach the ground be t.
The time interval between the first and third drops = 2t (since the third drop leaves the tap when the first drop touches the ground).
Let the velocity of the third drop be v3 when it leaves the tap.
Using the second equation of motion, we know that the distance covered by the third drop in time t is given as:
h = 0.5 × g × t²
⇒ t = √(2h/g) = √(2 × 5/10) = 1 s
Thus, the time interval between the first and third drops is 2t = 2 s.
Using the first equation of motion, we know that the velocity of the third drop when it reaches the ground is given as:
v3 = u + gt
where u = 0 (since the initial velocity is zero).
⇒ v3 = 10 m/s
Now, let the velocity of the second drop be v2 when the first drop touches the ground.
Since the second drop has travelled half the distance covered by the third drop in the same time interval, its time of flight is t/2.
Using the first equation of motion, we know that the velocity of the second drop when it reaches the ground is given as:
v2 = u + gt/2
where u = 0 (since the initial velocity is zero).
⇒ v2 = 5 m/s
Using the third equation of motion, we know that the height of the second drop at the instant when the first drop touches the ground is given as:
h2 = h - 0.5 × g × (t/2)²
⇒ h2 = 5 - 0.5 × 10 × (1/2)² = 3.75 m
Therefore, the height of the second drop at the instant when the first drop touches the ground is 3.75 m.
Hence, option (c) is the correct answer.
To find: height of the second drop at the instant when the first drop touches the ground.
Solution:
Let the time taken by each drop to reach the ground be t.
The time interval between the first and third drops = 2t (since the third drop leaves the tap when the first drop touches the ground).
Let the velocity of the third drop be v3 when it leaves the tap.
Using the second equation of motion, we know that the distance covered by the third drop in time t is given as:
h = 0.5 × g × t²
⇒ t = √(2h/g) = √(2 × 5/10) = 1 s
Thus, the time interval between the first and third drops is 2t = 2 s.
Using the first equation of motion, we know that the velocity of the third drop when it reaches the ground is given as:
v3 = u + gt
where u = 0 (since the initial velocity is zero).
⇒ v3 = 10 m/s
Now, let the velocity of the second drop be v2 when the first drop touches the ground.
Since the second drop has travelled half the distance covered by the third drop in the same time interval, its time of flight is t/2.
Using the first equation of motion, we know that the velocity of the second drop when it reaches the ground is given as:
v2 = u + gt/2
where u = 0 (since the initial velocity is zero).
⇒ v2 = 5 m/s
Using the third equation of motion, we know that the height of the second drop at the instant when the first drop touches the ground is given as:
h2 = h - 0.5 × g × (t/2)²
⇒ h2 = 5 - 0.5 × 10 × (1/2)² = 3.75 m
Therefore, the height of the second drop at the instant when the first drop touches the ground is 3.75 m.
Hence, option (c) is the correct answer.
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The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at an instant when the first drop touches the ground. How far above the ground is the second drop at that instant ? (Take g = 10 m/s2)[1995]a)1.25 mb)2.50 mc)3.75 md)5.00 mCorrect answer is option 'C'. Can you explain this answer?
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The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at an instant when the first drop touches the ground. How far above the ground is the second drop at that instant ? (Take g = 10 m/s2)[1995]a)1.25 mb)2.50 mc)3.75 md)5.00 mCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at an instant when the first drop touches the ground. How far above the ground is the second drop at that instant ? (Take g = 10 m/s2)[1995]a)1.25 mb)2.50 mc)3.75 md)5.00 mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at an instant when the first drop touches the ground. How far above the ground is the second drop at that instant ? (Take g = 10 m/s2)[1995]a)1.25 mb)2.50 mc)3.75 md)5.00 mCorrect answer is option 'C'. Can you explain this answer?.
The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at an instant when the first drop touches the ground. How far above the ground is the second drop at that instant ? (Take g = 10 m/s2)[1995]a)1.25 mb)2.50 mc)3.75 md)5.00 mCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at an instant when the first drop touches the ground. How far above the ground is the second drop at that instant ? (Take g = 10 m/s2)[1995]a)1.25 mb)2.50 mc)3.75 md)5.00 mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The water drops fall at regular intervals from a tap 5 m above the ground. The third drop is leaving the tap at an instant when the first drop touches the ground. How far above the ground is the second drop at that instant ? (Take g = 10 m/s2)[1995]a)1.25 mb)2.50 mc)3.75 md)5.00 mCorrect answer is option 'C'. Can you explain this answer?.
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