A sum of Rs. 8000 is borrowed at 5% p.a. compound interest and paid ba...
Let the repayment annually be X. Then: 8000 + 3 years interest on 8000 (on compound interest of 5%) = X + 2 years interest on X + X + 1 years interest on X + X → X = 2937.67
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A sum of Rs. 8000 is borrowed at 5% p.a. compound interest and paid ba...
Given:
Principal amount, P = Rs. 8000
Rate of interest, r = 5%
Time period, n = 3 years
Annual instalment is to be paid back in 3 equal parts
Formula Used:
Compound Interest = P(1 + r/n)^(n*t)
Amount = P(1 + r/n)^(n*t)
EMI = [P*r*(1+r)^n]/[(1+r)^n - 1]
Calculation:
As the amount is to be paid back in 3 equal annual instalments, let the amount of each instalment be E.
Amount to be paid back after 1st year, A1 = P(1+r/n)^(n*1) = 8000(1+0.05/1)^(1*1) = Rs. 8400
Amount to be paid back after 2nd year, A2 = P(1+r/n)^(n*2) = 8000(1+0.05/1)^(1*2) = Rs. 8820
Amount to be paid back after 3rd year, A3 = P(1+r/n)^(n*3) = 8000(1+0.05/1)^(1*3) = Rs. 9261
From the above calculation, we can say that the sum of three instalments is equal to Rs. 8000 + Rs. 8400 + Rs. 8820 = Rs. 25220
Hence, the amount of each instalment can be calculated using the formula of EMI
EMI = [P*r*(1+r)^n]/[(1+r)^n - 1]
EMI = [8000*0.05*(1+0.05)^3]/[(1+0.05)^3 - 1]
EMI = Rs. 2937.67
Therefore, the amount of each instalment is Rs. 2937.67 (Option A)