Given:
Mass of the object (m) = 1 kg
Initial speed (v) = 8 m/s
Force (F) = 2 N
Time (t) = 5 seconds

To find:
Speed after 5 seconds

Explanation:

1. Initial velocity:
The object is initially moving along the x-axis with a constant speed of 8 m/s. Since there is no force acting in the x-direction, the velocity in the x-direction remains constant.

2. Applied force:
A constant force of 2 N is applied in the positive y-direction. This force acts perpendicular to the velocity vector, so it does not affect the speed in the x-direction. However, it will cause a change in the object's velocity in the y-direction.

3. Newton's second law:
According to Newton's second law of motion, the net force acting on an object is equal to the product of its mass and acceleration. In this case, the net force in the y-direction is given by the applied force (F) and the acceleration (a).

4. Acceleration:
The acceleration can be calculated using the equation:
F = ma
2 N = 1 kg * a
a = 2 m/s²

5. Time:
Given that the time (t) is 5 seconds.

6. Final velocity:
Using the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

In the x-direction, the initial velocity (u) is 8 m/s, and there is no acceleration. Therefore, the velocity in the x-direction remains constant at 8 m/s.

In the y-direction, the initial velocity (u) is 0 m/s (since the object was not moving in the y-direction initially), the acceleration (a) is 2 m/s², and the time (t) is 5 seconds.

Substituting the values into the equation:
v = 0 + (2 m/s²) * (5 s)
v = 10 m/s

Conclusion:
After 5 seconds, the object will have a speed of 10 m/s in the y-direction while maintaining a constant speed of 8 m/s in the x-direction.

Because x direction mein koi force nhi lg rha toh acc toh zero hona chahiye toh velocity constant rhega