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Find the ratio in which the line 3X+4y-9 =0 divides the line segment joining the points (1,3) and (2,7)
Most Upvoted Answer
Find the ratio in which the line 3X+4y-9 =0 divides the line segment j...
Introduction:
In this problem, we are required to find the ratio in which the line 3x + 4y - 9 = 0 divides the line segment joining the points (1,3) and (2,7).

Method:
To solve this problem, we will use the section formula.

Section Formula:
The section formula is used to find the coordinates of a point which divides a line segment into two parts in a given ratio.

Let the line segment joining the points (x1,y1) and (x2,y2) be divided in the ratio of m:n by a point (x,y). Then the coordinates of the point (x,y) are given by:

x = (nx2 + mx1) / (m + n)
y = (ny2 + my1) / (m + n)

Solution:
Given the line 3x + 4y - 9 = 0, we can write it in the form of y = mx + c as follows:

4y = -3x + 9
y = (-3/4)x + (9/4)

Let (x,y) be the point where the line 3x + 4y - 9 = 0 intersects the line segment joining (1,3) and (2,7) in the ratio m:n. Then we have:

x = (nx2 + mx1) / (m + n)
y = (ny2 + my1) / (m + n)

Substituting the values, we get:

x = (n*2 + m*1) / (m + n)
y = (n*7 + m*3) / (m + n)

Since the point (x,y) lies on the line 3x + 4y - 9 = 0, we have:

3x + 4y - 9 = 0

Substituting the value of y from the above equation, we get:

3x + 4[(n*7 + m*3) / (m + n)] - 9 = 0

Simplifying the above equation, we get:

(3n - 4m)x + 28n - 12m - 36 = 0

Since the above equation is true for all values of x, the coefficients of x and the constant term must be equal to zero. Therefore, we have:

3n - 4m = 0 (1)
28n - 12m - 36 = 0 (2)

Solving the above two equations, we get:

m:n = 7:12

Therefore, the line 3x + 4y - 9 = 0 divides the line segment joining (1,3) and (2,7) in the ratio of 7:12.

Conclusion:
Hence, we have found the ratio in which the line 3x + 4y - 9 = 0 divides the line segment joining the points (1,3) and (2,7) using the section formula.
Community Answer
Find the ratio in which the line 3X+4y-9 =0 divides the line segment j...
Let the line 3x +4y-9=0 divides the lines segment joining A(1,3) and B(2,7) in ratio k:1 at point p.

therefore, coordinates of p= (2k+1/k+1,7k+3/k+1)


since, p lies on the line 3x+4y -9=0
so coordinates of p satisfies 3x +4y -9=0


=> 3(2k +1/k +1) +4(7k +3/k +1) -9 =0
=> 6k+3 +28 k +12 -9k -9=0
=> 25k +6=0

=>k= 6/24


line 3x+4y-9=0 divides the line segment joining the points A and B in 6:25 externally.


I hope it helps you :)
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Find the ratio in which the line 3X+4y-9 =0 divides the line segment joining the points (1,3) and (2,7) for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Find the ratio in which the line 3X+4y-9 =0 divides the line segment joining the points (1,3) and (2,7) covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the ratio in which the line 3X+4y-9 =0 divides the line segment joining the points (1,3) and (2,7).
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