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For the RLC parallel resonant circuit when R = 8 kΩ , L = 40 mH and C = 0.25 μF, the quality factor Q is
- a)40
- b)20
- c)30
- d)10
Correct answer is option 'B'. Can you explain this answer?
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For the RLC parallel resonant circuit when R = 8 kΩ , L =40 mH a...
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For the RLC parallel resonant circuit when R = 8 kΩ , L =40 mH a...
Ω, L = 2 mH, and C = 10 nF, the resonant frequency can be found using the formula:
fr = 1 / (2π√(LC))
Substituting the given values, we get:
fr = 1 / (2π√(2 × 10^-3 × 10 × 10^-9))
fr = 1 / (2π√(2 × 10^-12))
fr = 1 / (2π × 1.414 × 10^-6)
fr = 112.15 kHz
Therefore, the resonant frequency of the RLC parallel resonant circuit is 112.15 kHz.
fr = 1 / (2π√(LC))
Substituting the given values, we get:
fr = 1 / (2π√(2 × 10^-3 × 10 × 10^-9))
fr = 1 / (2π√(2 × 10^-12))
fr = 1 / (2π × 1.414 × 10^-6)
fr = 112.15 kHz
Therefore, the resonant frequency of the RLC parallel resonant circuit is 112.15 kHz.
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For the RLC parallel resonant circuit when R = 8 kΩ , L =40 mH and C = 0.25 μF, the quality factor Q isa)40b)20c)30d)10Correct answer is option 'B'. Can you explain this answer?
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