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Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per annum simple interest and Rs. 24,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3,680. The rate of interest per annum, at which the remaining money is lent, is ?
  • a)
    5%
  • b)
    7%
  • c)
    10%
  • d)
    12%
  • e)
    None of the Above
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per ann...
Ans.

Remaining amount

= Rs (50000 - (8000 + 24000)

= Rs 18000

Let Rs 18000 be lent at the rate of r% p.a

According to the question,

8000�11�1/2�100 + 24000�6�x/100 + 18000�r�1/100 = 3680

=> 440 + 1440 + 180r = 3680

=> 1880 + 180r = 3680

=> 180r = 3680 - 1880 = 1800

=> r = 1800180
= 10%
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Most Upvoted Answer
Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per ann...
Solution:

Given,
Total sum = Rs. 50,000
Amount lent at 11/2 % per annum = Rs. 8,000
Amount lent at 6% per annum = Rs. 24,000
Total annual interest = Rs. 3,680

Let the remaining amount be x and the rate of interest be r.

Calculation:
1. Interest on Rs. 8,000 at 11/2 % per annum
= (11/2) × (8000/100)
= Rs. 440

2. Interest on Rs. 24,000 at 6% per annum
= (6 × 24000)/100
= Rs. 1440

3. Interest on remaining amount x at rate r
= (r × x)/100

From the given information,
Total annual interest = Rs. 3,680
⇒ 440 + 1440 + (rx/100) = 3680
⇒ (rx/100) = 1800
⇒ rx = 180000
⇒ x = 180000/r

Substituting the value of x in the above equation, we get
(180000r)/10000 = 1800
⇒ r = 10%

Therefore, the rate of interest per annum, at which the remaining money is lent, is 10%.

Hence, option (c) is the correct answer.
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Community Answer
Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per ann...
C. 10%
Explanation: Total Amount = 50000 Amount divided into three parts – x, y, z x = 8000, T = 1 yr SI(x) = (8000 * 11/2)/100 = 440 y = 24000 R = 6% SI(y) = (24000 * 6)/100 = 1440 Total Interest = 3680, Interest on the remaining amount = 3680 – 440 – 1440 = 1800
z = 50000 – 24000 – 8000 = 18000 R = (1800 * 100) /18000 = 10%
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Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per annum simple interest and Rs. 24,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3,680. The rate of interest per annum, at which the remaining money is lent, is ?a)5%b)7%c)10%d)12%e)None of the AboveCorrect answer is option 'C'. Can you explain this answer?
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Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per annum simple interest and Rs. 24,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3,680. The rate of interest per annum, at which the remaining money is lent, is ?a)5%b)7%c)10%d)12%e)None of the AboveCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per annum simple interest and Rs. 24,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3,680. The rate of interest per annum, at which the remaining money is lent, is ?a)5%b)7%c)10%d)12%e)None of the AboveCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per annum simple interest and Rs. 24,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3,680. The rate of interest per annum, at which the remaining money is lent, is ?a)5%b)7%c)10%d)12%e)None of the AboveCorrect answer is option 'C'. Can you explain this answer?.
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