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A man borrows 10000 rupees at 20 % compound interest for 3 years. If every year he pays 2000 rupees as repayment. How much amount is still left to be paid by the man?
  • a)
    5000
  • b)
    7000
  • c)
    9000
  • d)
    10000
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A man borrows 10000 rupees at 20 % compound interest for 3 years. If e...
Amount to be paid at the end of three years = 10000*(1+20/100)3 = 17280
Amount paid as instalment by the man = 2000*(1+20/100)2 + 2000*(1+20/100) + 2000 = 7280
So remaining amount = 10000
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A man borrows 10000 rupees at 20 % compound interest for 3 years. If e...
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A man borrows 10000 rupees at 20 % compound interest for 3 years. If e...
To solve this problem, we need to calculate the compound interest for 3 years and subtract the repayment amount from the borrowed amount.

Step 1: Calculate the compound interest
The compound interest formula is given by:
A = P(1 + r/n)^(nt)
Where:
A = the final amount (including interest)
P = the principal amount (borrowed amount)
r = annual interest rate (in decimal form)
n = number of times interest is compounded per year
t = time in years

Given:
P = 10000 rupees
r = 20% = 0.20 (converted to decimal)
n = 1 (compounded annually)
t = 3 years

Using the compound interest formula:
A = 10000(1 + 0.20/1)^(1*3)
A = 10000(1 + 0.20)^3
A = 10000(1.20)^3
A = 10000(1.728)
A = 17280 rupees

Step 2: Calculate the remaining amount to be paid
The man repays 2000 rupees every year for 3 years.
Total repayment = 2000 * 3 = 6000 rupees

Remaining amount to be paid = A - Total repayment
Remaining amount = 17280 - 6000
Remaining amount = 11280 rupees

Therefore, the amount still left to be paid by the man is 11280 rupees, which corresponds to option 'D'.
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A man borrows 10000 rupees at 20 % compound interest for 3 years. If every year he pays 2000 rupees as repayment. How much amount is still left to be paid by the man?a)5000b)7000c)9000d)10000e)None of theseCorrect answer is option 'D'. Can you explain this answer?
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