Two taps can separately fill the tank in 10m and 15min respectively. T...
1/10 + 1/ 15 - 1/x =1/12 //x is the time taken by C to empty the tank
1/x = 5/60
x = 12
Two taps can separately fill the tank in 10m and 15min respectively. T...
Given information:
- The first tap can fill the tank in 10 minutes.
- The second tap can fill the tank in 15 minutes.
- When a third pipe is opened, the tank is filled in 12 minutes.
To find: The time taken by the third pipe to empty the whole tank.
Let's assume that the capacity of the tank is 60 units (LCM of 10 and 15 minutes).
Let's calculate the rate of filling for each tap:
- The first tap can fill 60 units in 10 minutes, so its filling rate is 60/10 = 6 units per minute.
- The second tap can fill 60 units in 15 minutes, so its filling rate is 60/15 = 4 units per minute.
Now, let's determine the combined filling rate of the first two taps when the third pipe is opened:
- In 12 minutes, the first two taps fill the tank completely, which is 60 units.
- So, the combined filling rate is 60/12 = 5 units per minute.
Since the third pipe empties the tank, its filling rate will be negative.
Let's assume the filling rate of the third pipe is x units per minute (negative).
According to the given information, when the first two taps are open along with the third pipe, the tank is filled in 12 minutes.
Using the concept of rate and time, we can write the equation:
6 + 4 + x = 5
Simplifying the equation, we get:
10 + x = 5
x = -5
Therefore, the filling rate of the third pipe is -5 units per minute, which means it empties 5 units of the tank per minute.
Finally, to find the time taken by the third pipe to empty the whole tank, we divide the capacity of the tank (60 units) by the rate of empting (5 units per minute):
Time taken = 60/5 = 12 minutes.
Hence, the correct answer is option C) 12 minutes.