Two pipes P and Q can fill a tank in 10 min and 12 min respectively an...
Let the waste pipe take ‘T’ time to empty the tank.
(1/10 + 1/12 – 1/T)*60 = -1
We will get T = 5 min
So capacity = 5*12 = 60ltr
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Two pipes P and Q can fill a tank in 10 min and 12 min respectively an...
Problem:
Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.
Solution:
Let the capacity of the tank be 'x' litres.
Given, Pipe P can fill the tank in 10 minutes. So, the amount of water it can fill in 1 minute is x/10 litres.
Similarly, Pipe Q can fill the tank in 12 minutes. So, the amount of water it can fill in 1 minute is x/12 litres.
The waste pipe can carry off 12 litres of water per minute. So, the net amount of water filled in 1 minute when all pipes are opened is (x/10 + x/12 - 12) litres.
It takes 1 hour to empty the tank. So, the amount of water emptied in 1 minute is x/60 litres.
Therefore, the net amount of water filled in 1 minute is equal to the amount of water emptied in 1 minute. Hence, we can write the equation as follows:
x/10 + x/12 - 12 = x/60
Solving this equation, we get x = 60 litres.
Answer:
The capacity of the tank is 60 litres. Therefore, the correct answer is option (c).
Two pipes P and Q can fill a tank in 10 min and 12 min respectively an...
Let the waste pipe take ‘T’ time to empty the tank.
(1/10 + 1/12 – 1/T)*60 = -1
We will get T = 5 min
So capacity = 5*12 = 60ltr