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If A is point on the x – axis whose abscissa is 5 and B is the point (1, – 3), then the distance AB is
  • a)
    25 units
  • b)
    5 units
  • c)
    8 units
  • d)
    9 units
Correct answer is option 'B'. Can you explain this answer?
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If A is point on the x – axis whose abscissa is 5 and B is the p...
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If A is point on the x – axis whose abscissa is 5 and B is the p...
Given information:
- Point A is on the x-axis with an abscissa (x-coordinate) of 5.
- Point B is located at coordinates (1, 3).

To find:
The distance between points A and B.

Solution:
We can use the distance formula to find the distance between two points in a coordinate plane. The distance formula is given by:

d = √((x2 - x1)^2 + (y2 - y1)^2)

Where (x1, y1) and (x2, y2) are the coordinates of the two points.

Step 1: Identify the coordinates of points A and B:
- Point A is on the x-axis, so its y-coordinate is 0. Therefore, A is located at (5, 0).
- Point B is given as (1, 3).

Step 2: Substitute the coordinates into the distance formula:
d = √((1 - 5)^2 + (3 - 0)^2)
= √((-4)^2 + 3^2)
= √(16 + 9)
= √25
= 5

Therefore, the distance between points A and B is 5 units.

Answer:
The correct answer is option 'B' - 5 units.
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Community Answer
If A is point on the x – axis whose abscissa is 5 and B is the p...
Explanation:
Since A is a point on the x - axis, therefore coordinates of A are (5 , 0)
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If A is point on the x – axis whose abscissa is 5 and B is the point (1, – 3), then the distance AB isa)25 unitsb)5 unitsc)8 unitsd)9 unitsCorrect answer is option 'B'. Can you explain this answer?
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