Shrinkage limit of clay is 23% and its natural water content 32% decre...
Calculation of Decrease in Volume of Clay
Given:
- Shrinkage limit of clay = 23%
- Natural water content of clay = 32%
- Reduction in moisture content of clay = 14%
- Specific gravity of clay (g) = 2.65
Calculation:
The volume of clay (V1) at natural water content can be calculated as:
V1 = (100 / (100 + w)) * M
Where,
- w = natural water content of clay = 32%
- M = mass of clay
Thus, V1 = (100 / (100 + 32)) * M = 0.735M
The volume of clay (V2) at reduced moisture content can be calculated as:
V2 = (100 / (100 + (w - r))) * M
Where,
- r = reduction in moisture content of clay = 14%
Thus, V2 = (100 / (100 + (32 - 14))) * M = 0.642M
The decrease in volume of clay due to reduction in moisture content can be calculated as:
Decrease in volume = V1 - V2
Thus, Decrease in volume = 0.735M - 0.642M = 0.093M
The final volume of clay (V3) after reduction in moisture content can be calculated as:
V3 = V2 - (V2 * s)
Where,
- s = shrinkage limit of clay = 23%
Thus, V3 = 0.642M - (0.642M * 0.23) = 0.494M
The percentage decrease in volume of clay can be calculated as:
Percentage decrease in volume = (Decrease in volume / V1) * 100
Thus, Percentage decrease in volume = (0.093M / 0.735M) * 100 = 12.65%
Answer:
The decrease in volume of clay due to reduction in moisture content by 14% will be 0.093M. The final volume of clay after reduction in moisture content will be 0.494M. The percentage decrease in volume of clay will be 12.65%.