Two fair dice are thrown. What is the probability of (i) throwing a do...
The probability of throwing a double when two fair dice are thrown can be calculated by considering the total number of possible outcomes and the number of favorable outcomes.
Total Number of Outcomes:
When two dice are thrown, each dice has 6 possible outcomes (numbers 1 to 6). Therefore, the total number of outcomes for throwing two dice is 6 * 6 = 36.
Favorable Outcomes:
A double is when both dice show the same number. There are 6 possible doubles: (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6).
Probability Calculation:
The probability of an event is given by the formula:
Probability = Number of Favorable Outcomes / Total Number of Outcomes
In this case, the number of favorable outcomes is 6 (since there are 6 possible doubles) and the total number of outcomes is 36.
Probability = 6 / 36 = 1 / 6
Hence, the probability of throwing a double is 1/6.
Explanation:
When two fair dice are thrown, the probability of getting a double is 1/6 because there are 6 possible doubles out of a total of 36 possible outcomes. Each outcome is equally likely to occur, so the probability is calculated by dividing the number of favorable outcomes (6) by the total number of outcomes (36). This simplifies to 1/6. Thus, option 'A' is the correct answer.