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When ordinary light is passed through rotating crystal, there is no variation in the intensity of the emergent light, this implies that
- a)Ordinary light is symmetrical about its direction of propagation
- b)Ordinary light is polarized about its direction of propagation
- c)Ordinary light is unsymmetrical about its direction of motion
- d)None of the above
Correct answer is option 'A'. Can you explain this answer?
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When ordinary light is passed through rotating crystal, there is no va...
The correct answer is: Ordinary light is symmetrical about its direction of propagation
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When ordinary light is passed through rotating crystal, there is no va...
Explanation:
When ordinary light is passed through a rotating crystal, there is no variation in the intensity of the emergent light. This implies that ordinary light is symmetrical about its direction of propagation.
Reasoning:
To understand this, we need to consider the effect of passing light through a rotating crystal. When light passes through a crystal, it interacts with the crystal lattice and its polarization state may change. The crystal lattice can act as a polarizer and selectively transmit light waves with a specific polarization orientation.
Effect of a rotating crystal:
1. When a crystal is not rotating, it acts as a static polarizer. It transmits light waves with a specific polarization orientation, while blocking the waves with perpendicular polarization.
2. When a crystal is rotating, its orientation changes with time. As a result, the transmitted polarization direction also changes continuously. However, the rotation does not affect the intensity of the transmitted light.
Explanation:
When ordinary light is incident on a rotating crystal, it consists of a mixture of light waves with different polarization orientations. As the crystal rotates, the transmitted polarization direction continuously changes. However, since ordinary light is symmetrical about its direction of propagation, it contains equal components of all possible polarization orientations.
As a result, when the crystal rotates, the transmitted light still contains equal components of all possible polarization orientations. This leads to a constant intensity of the emergent light, regardless of the crystal's rotation.
Conclusion:
Therefore, the lack of variation in the intensity of the emergent light when ordinary light is passed through a rotating crystal implies that ordinary light is symmetrical about its direction of propagation.
When ordinary light is passed through a rotating crystal, there is no variation in the intensity of the emergent light. This implies that ordinary light is symmetrical about its direction of propagation.
Reasoning:
To understand this, we need to consider the effect of passing light through a rotating crystal. When light passes through a crystal, it interacts with the crystal lattice and its polarization state may change. The crystal lattice can act as a polarizer and selectively transmit light waves with a specific polarization orientation.
Effect of a rotating crystal:
1. When a crystal is not rotating, it acts as a static polarizer. It transmits light waves with a specific polarization orientation, while blocking the waves with perpendicular polarization.
2. When a crystal is rotating, its orientation changes with time. As a result, the transmitted polarization direction also changes continuously. However, the rotation does not affect the intensity of the transmitted light.
Explanation:
When ordinary light is incident on a rotating crystal, it consists of a mixture of light waves with different polarization orientations. As the crystal rotates, the transmitted polarization direction continuously changes. However, since ordinary light is symmetrical about its direction of propagation, it contains equal components of all possible polarization orientations.
As a result, when the crystal rotates, the transmitted light still contains equal components of all possible polarization orientations. This leads to a constant intensity of the emergent light, regardless of the crystal's rotation.
Conclusion:
Therefore, the lack of variation in the intensity of the emergent light when ordinary light is passed through a rotating crystal implies that ordinary light is symmetrical about its direction of propagation.
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When ordinary light is passed through rotating crystal, there is no variation in the intensity of the emergent light, this implies thata)Ordinary light is symmetrical about its direction of propagationb)Ordinary light is polarized about its direction of propagationc)Ordinary light is unsymmetrical about its direction of motiond)None of the aboveCorrect answer is option 'A'. Can you explain this answer?
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When ordinary light is passed through rotating crystal, there is no variation in the intensity of the emergent light, this implies thata)Ordinary light is symmetrical about its direction of propagationb)Ordinary light is polarized about its direction of propagationc)Ordinary light is unsymmetrical about its direction of motiond)None of the aboveCorrect answer is option 'A'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about When ordinary light is passed through rotating crystal, there is no variation in the intensity of the emergent light, this implies thata)Ordinary light is symmetrical about its direction of propagationb)Ordinary light is polarized about its direction of propagationc)Ordinary light is unsymmetrical about its direction of motiond)None of the aboveCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When ordinary light is passed through rotating crystal, there is no variation in the intensity of the emergent light, this implies thata)Ordinary light is symmetrical about its direction of propagationb)Ordinary light is polarized about its direction of propagationc)Ordinary light is unsymmetrical about its direction of motiond)None of the aboveCorrect answer is option 'A'. Can you explain this answer?.
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