The depth of the dam is 240m . The pressure of water is(take g=10m/s^2 and density of liquid=1000kg/m^3) Ans=2.4×10^6 N/m^2 Plz tell me how the ans came?

Question

Answer

Answer

Answer

The pressure of water at a certain depth can be calculated using the formula:

Pressure = density x gravity x depth

Where:
- Density is the density of the liquid (given as 1000 kg/m^3)
- Gravity is the acceleration due to gravity (given as 10 m/s^2)
- Depth is the depth of the dam (given as 240 m)

Now, let's calculate the pressure of water in the dam using the given values:

Step 1: Write down the given values:
Density = 1000 kg/m^3
Gravity = 10 m/s^2
Depth = 240 m

Step 2: Substitute the values into the formula:
Pressure = 1000 kg/m^3 x 10 m/s^2 x 240 m

Step 3: Simplify the equation:
Pressure = 1000 x 10 x 240 kg m^-1 s^-2

Step 4: Perform the multiplication:
Pressure = 2,400,000 kg m^-1 s^-2

Step 5: Convert the units to N/m^2:
1 N = 1 kg m/s^2
Pressure = 2,400,000 N/m^2

Therefore, the pressure of water at a depth of 240 m in the dam is 2.4 x 10^6 N/m^2.

Summary:
- Given values: Density = 1000 kg/m^3, Gravity = 10 m/s^2, Depth = 240 m
- Using the formula Pressure = density x gravity x depth, substitute the values
- Simplify the equation and perform the multiplication
- Convert the units to N/m^2
- The final answer is 2.4 x 10^6 N/m^2.

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