NEET Exam > NEET Questions > A ball is projected so as to pass a wall at a...
Start Learning for Free
A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question?
Most Upvoted Answer
A ball is projected so as to pass a wall at a distance a from the poin...
Projectile Motion Problem
In this problem, we are given that a ball is projected at an angle of 45 degrees from a point such that it passes over a wall at a distance a from the point of projection and falls at a distance b on the other side of the wall. We need to find the height of the wall.
Solution Steps
1. Analyze the Projectile Motion
The motion of the ball can be analyzed using the equations of projectile motion. The horizontal and vertical components of the velocity at any point during the motion can be determined as follows:
vx = v cos θ
vy = v sin θ - gt
where v is the initial velocity of the ball, θ is the angle of projection, g is the acceleration due to gravity, and t is the time elapsed.
2. Find the Time of Flight
The time taken by the ball to travel a distance of a + b horizontally can be determined by using the horizontal component of the velocity:
a + b = vx t
t = (a + b) / vx
3. Find the Maximum Height
The maximum height reached by the ball can be determined by using the vertical component of the velocity:
vy = 0 at the maximum height
v sin θ - gt = 0
t = v sin θ / g
hmax = vy t - 1/2 g t^2
hmax = v^2 sin^2 θ / 2g
4. Find the Height of the Wall
The height of the wall can be determined by subtracting the maximum height from the height of the ball when it passes over the wall:
h = hmax - (a tan θ)
Substituting the values of hmax and θ, we get:
h = (v^2 / 2g) - a
Using the equation of time of flight, we can express v in terms of a and b:
v = (a + b) / (cos θ t)
Substituting this value of v in the equation for h, we get:
h = (ab / a + b)
Therefore, the height of the wall is given by h = ab / (a + b).
In this problem, we are given that a ball is projected at an angle of 45 degrees from a point such that it passes over a wall at a distance a from the point of projection and falls at a distance b on the other side of the wall. We need to find the height of the wall.
Solution Steps
1. Analyze the Projectile Motion
The motion of the ball can be analyzed using the equations of projectile motion. The horizontal and vertical components of the velocity at any point during the motion can be determined as follows:
vx = v cos θ
vy = v sin θ - gt
where v is the initial velocity of the ball, θ is the angle of projection, g is the acceleration due to gravity, and t is the time elapsed.
2. Find the Time of Flight
The time taken by the ball to travel a distance of a + b horizontally can be determined by using the horizontal component of the velocity:
a + b = vx t
t = (a + b) / vx
3. Find the Maximum Height
The maximum height reached by the ball can be determined by using the vertical component of the velocity:
vy = 0 at the maximum height
v sin θ - gt = 0
t = v sin θ / g
hmax = vy t - 1/2 g t^2
hmax = v^2 sin^2 θ / 2g
4. Find the Height of the Wall
The height of the wall can be determined by subtracting the maximum height from the height of the ball when it passes over the wall:
h = hmax - (a tan θ)
Substituting the values of hmax and θ, we get:
h = (v^2 / 2g) - a
Using the equation of time of flight, we can express v in terms of a and b:
v = (a + b) / (cos θ t)
Substituting this value of v in the equation for h, we get:
h = (ab / a + b)
Therefore, the height of the wall is given by h = ab / (a + b).
Community Answer
A ball is projected so as to pass a wall at a distance a from the poin...
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question?
Question Description
A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question?.
A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question?.
Solutions for A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question? defined & explained in the simplest way possible. Besides giving the explanation of
A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question?, a detailed solution for A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question? has been provided alongside types of A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question? theory, EduRev gives you an
ample number of questions to practice A ball is projected so as to pass a wall at a distance a from the point of projection at an angle of 45 degree and falls at a distance b on the other side of the wall .if h is the hight of the wall then answer is h=ab/a b can anyone explain this question? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup