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What is the electric field intensity at a distance of 20cm from a charge 2 X 10-6 C in vacuum? 
  • a)
    250,000
  • b)
    350,000
  • c)
    450,000
  • d)
    550,000
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What is the electric field intensity at a distance of 20cm from a char...
Answer: c
Explanation: E = Q/ (4∏εor2)
= (2 X 10-6)/(4∏ X εo X 0.22) = 450,000 V/m
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Most Upvoted Answer
What is the electric field intensity at a distance of 20cm from a char...
Given:
Charge(q) = 2 x 10^-6 C
Distance(r) = 20cm = 0.2m
Permittivity of free space(ε0) = 8.854 x 10^-12 F/m

Formula:
Electric Field Intensity(E) = q / (4πε0r^2)

Calculation:
Substituting the given values in the formula, we get
E = (2 x 10^-6) / (4π x 8.854 x 10^-12 x 0.2^2)
E = 4.5 x 10^5 N/C

Therefore, the electric field intensity at a distance of 20cm from a charge 2 x 10^-6C in vacuum is 450,000 N/C, which is option C.
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What is the electric field intensity at a distance of 20cm from a charge 2 X 10-6C in vacuum?a)250,000b)350,000c)450,000d)550,000Correct answer is option 'C'. Can you explain this answer?
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