In a double slit interference experiment d is the distance between the centres of theslits andw is the width of each slit.Find the minimum integer ratio d/ωfor which aninterference maximum of incident plane waves on a distant screen will be missing.Correct answer is '2'. Can you explain this answer?

Question

In a double slit interference experiment d is the distance between the centres of theslits andw is the width of each slit.Find the minimum integer ratio d/&omega;for which aninterference maximum of incident plane waves on a distant screen will be missing.Correct answer is '2'. Can you explain this answer?

Answer

To find the minimum integer ratio of d, we need to simplify the expression d/w as much as possible.

We know that both d and w are positive quantities, so we can assume that d > w.

To simplify d/w, we can divide both the numerator and denominator by the greatest common divisor (gcd) of d and w.

Let's say gcd(d, w) = x.

Then, we can write d = xa and w = xb, where a and b are positive integers greater than 1, and gcd(a, b) = 1.

Now, d/w = (xa)/(xb) = a/b.

Since a/b is a ratio of two positive integers, the minimum integer ratio of d/w is a/b.

Therefore, the minimum integer ratio of d is a.

Similar Physics Doubts

Two identical coherent waves produce Interference pattern. Then find the ratio of intensity at the centre of a bright fringe to the intensity at a point one quarter of the distance between two fringes from the centre _____ . Correct answer is '2'. Can you explain this answer?

Which of the following are not true about interferences?

Top Courses for Physics

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams