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In a class of 50 students, 70% students pass in QA, 90% pass in EU and 60% pass in RC. What is the minimum percentage of students who pass in all the papers?
- a)15%
- b)30%
- c)40%
- d)20%
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
In a class of 50 students, 70% students pass in QA, 90% pass in EU and...
We can do this question by using either the formula for three sets, or we can simply keep on applying the formula for two sets required a number of times.
We know that n(A∪B) = n (A ) + n(B) - n(A∩B)
Assuming that n(Q) = number of students passing QA, n(E) = number of students passing EU and n(R) = number of students passing RC
Hence, n(Q∪R) = n(Q) + n(R) - n(Q∩R).
Or, n(Q∩R) = n(Q) + n(R) - n(QuR) = 70% + 60% - n(Q∪R)
Now the minimum value of n(Q∩R) will occur for the maximum value of n(Q∪R). The maximum possible value of n(Q∪R) =100%
So, the minimum value of n(Q∩R) = 30%
Now, the minimum value of EU, QA and RC will be obtained by finding the minimum of EU and (QA∩RC).
The minimum value of EU and (QA∩RC) = 90% + 30% - 100% = 20%
Most Upvoted Answer
In a class of 50 students, 70% students pass in QA, 90% pass in EU and...
Analysis:
To find the minimum percentage of students who pass in all the papers, we need to consider the students who passed in each individual paper and find the common percentage among them.
Given Information:
- Total number of students in the class = 50
- Percentage of students who pass in QA = 70%
- Percentage of students who pass in EU = 90%
- Percentage of students who pass in RC = 60%
Calculating the Number of Students:
- Number of students who pass in QA = (70/100) * 50 = 35
- Number of students who pass in EU = (90/100) * 50 = 45
- Number of students who pass in RC = (60/100) * 50 = 30
Calculating the Minimum Percentage:
To find the minimum percentage, we need to find the common percentage among the students who passed in all three papers.
Step 1:
We can start by assuming that all the students who passed in QA also passed in EU and RC. So, the number of students who passed in all three papers is 35.
Step 2:
Now, let's check if all the students who passed in EU also passed in RC. The number of students who passed in EU is 45, but the number of students who passed in both EU and RC is only 30. This means that there are 15 students who passed in EU but failed in RC.
Step 3:
Since the number of students who passed in all three papers is 35 and there are 15 students who passed in EU but failed in RC, the maximum number of students who passed in all three papers is 35 - 15 = 20.
Step 4:
Finally, we can calculate the minimum percentage of students who passed in all three papers by dividing the number of students who passed in all three papers (20) by the total number of students in the class (50) and multiplying by 100.
Minimum percentage = (20/50) * 100 = 40%
Therefore, the minimum percentage of students who pass in all the papers is 40%.
Answer:
The correct answer is option C) 40%.
To find the minimum percentage of students who pass in all the papers, we need to consider the students who passed in each individual paper and find the common percentage among them.
Given Information:
- Total number of students in the class = 50
- Percentage of students who pass in QA = 70%
- Percentage of students who pass in EU = 90%
- Percentage of students who pass in RC = 60%
Calculating the Number of Students:
- Number of students who pass in QA = (70/100) * 50 = 35
- Number of students who pass in EU = (90/100) * 50 = 45
- Number of students who pass in RC = (60/100) * 50 = 30
Calculating the Minimum Percentage:
To find the minimum percentage, we need to find the common percentage among the students who passed in all three papers.
Step 1:
We can start by assuming that all the students who passed in QA also passed in EU and RC. So, the number of students who passed in all three papers is 35.
Step 2:
Now, let's check if all the students who passed in EU also passed in RC. The number of students who passed in EU is 45, but the number of students who passed in both EU and RC is only 30. This means that there are 15 students who passed in EU but failed in RC.
Step 3:
Since the number of students who passed in all three papers is 35 and there are 15 students who passed in EU but failed in RC, the maximum number of students who passed in all three papers is 35 - 15 = 20.
Step 4:
Finally, we can calculate the minimum percentage of students who passed in all three papers by dividing the number of students who passed in all three papers (20) by the total number of students in the class (50) and multiplying by 100.
Minimum percentage = (20/50) * 100 = 40%
Therefore, the minimum percentage of students who pass in all the papers is 40%.
Answer:
The correct answer is option C) 40%.
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In a class of 50 students, 70% students pass in QA, 90% pass in EU and 60% pass in RC. What is the minimum percentage of students who pass in all the papers?a)15%b)30%c)40%d)20%Correct answer is option 'D'. Can you explain this answer?
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In a class of 50 students, 70% students pass in QA, 90% pass in EU and 60% pass in RC. What is the minimum percentage of students who pass in all the papers?a)15%b)30%c)40%d)20%Correct answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about In a class of 50 students, 70% students pass in QA, 90% pass in EU and 60% pass in RC. What is the minimum percentage of students who pass in all the papers?a)15%b)30%c)40%d)20%Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a class of 50 students, 70% students pass in QA, 90% pass in EU and 60% pass in RC. What is the minimum percentage of students who pass in all the papers?a)15%b)30%c)40%d)20%Correct answer is option 'D'. Can you explain this answer?.
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