Quant Exam > Quant Questions > A certain function always obeys the rule: If ...
Start Learning for Free
A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)
- a)128
- b)256
- c)512
- d)1024
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A certain function always obeys the rule: If f (x.y) = f(x). f(y) wher...
Since f (128) = 4, we can see that the product of f (256). f (0.5) = f (256 × 0.5) = f (128) = 4.
Similarly, the products f (1). f (128) = f (2). f (64)
= f (4). f (32) = f (8). f (16) = 4.
Thus, M = 4 × 4 × 4 × 4 × 4 = 1024.
Option (d) is the correct answer.
Similarly, the products f (1). f (128) = f (2). f (64)
= f (4). f (32) = f (8). f (16) = 4.
Thus, M = 4 × 4 × 4 × 4 × 4 = 1024.
Option (d) is the correct answer.
Most Upvoted Answer
A certain function always obeys the rule: If f (x.y) = f(x). f(y) wher...
Given information:
- f(x.y) = f(x).f(y) for positive real numbers x and y
- f(128) = 4
To find:
M = f(0.5) . f(1) . f(2) . f(4) . f(8) . f(16) . f(32) . f(64) . f(128) . f(256)
Solution:
We can use the given rule to simplify the expression for M. We start with f(1) and use it to find f(2), then use f(2) to find f(4), and so on, until we reach f(128). Then we can substitute the given value of f(128) and simplify the expression for M.
1. f(1) = f(0.5 . 2) = f(0.5) . f(2)
2. f(2) = f(1 . 2) = f(1) . f(2) = (f(0.5) . f(2)) . f(2) = f(0.5) . f(2)^2
3. f(4) = f(2 . 2) = f(2) . f(2) = f(0.5) . f(2)^2 . f(0.5) . f(2)^2 = f(0.5)^2 . f(2)^4
4. f(8) = f(4 . 2) = f(4) . f(2) = f(0.5)^2 . f(2)^4 . f(0.5) . f(2)^2 = f(0.5)^3 . f(2)^6
5. f(16) = f(8 . 2) = f(8) . f(2) = f(0.5)^3 . f(2)^6 . f(0.5) . f(2)^2 = f(0.5)^4 . f(2)^8
6. f(32) = f(16 . 2) = f(16) . f(2) = f(0.5)^4 . f(2)^8 . f(0.5) . f(2)^2 = f(0.5)^5 . f(2)^10
7. f(64) = f(32 . 2) = f(32) . f(2) = f(0.5)^5 . f(2)^10 . f(0.5) . f(2)^2 = f(0.5)^6 . f(2)^12
8. f(128) = f(64 . 2) = f(64) . f(2) = f(0.5)^6 . f(2)^12 . f(0.5) . f(2)^2 = f(0.5)^7 . f(2)^14 = 4
Substituting f(128) = 4 into the expression for M, we get:
M = f(0.5) . f(1) . f(2) . f(4) . f(8) . f(16) . f(32)
- f(x.y) = f(x).f(y) for positive real numbers x and y
- f(128) = 4
To find:
M = f(0.5) . f(1) . f(2) . f(4) . f(8) . f(16) . f(32) . f(64) . f(128) . f(256)
Solution:
We can use the given rule to simplify the expression for M. We start with f(1) and use it to find f(2), then use f(2) to find f(4), and so on, until we reach f(128). Then we can substitute the given value of f(128) and simplify the expression for M.
1. f(1) = f(0.5 . 2) = f(0.5) . f(2)
2. f(2) = f(1 . 2) = f(1) . f(2) = (f(0.5) . f(2)) . f(2) = f(0.5) . f(2)^2
3. f(4) = f(2 . 2) = f(2) . f(2) = f(0.5) . f(2)^2 . f(0.5) . f(2)^2 = f(0.5)^2 . f(2)^4
4. f(8) = f(4 . 2) = f(4) . f(2) = f(0.5)^2 . f(2)^4 . f(0.5) . f(2)^2 = f(0.5)^3 . f(2)^6
5. f(16) = f(8 . 2) = f(8) . f(2) = f(0.5)^3 . f(2)^6 . f(0.5) . f(2)^2 = f(0.5)^4 . f(2)^8
6. f(32) = f(16 . 2) = f(16) . f(2) = f(0.5)^4 . f(2)^8 . f(0.5) . f(2)^2 = f(0.5)^5 . f(2)^10
7. f(64) = f(32 . 2) = f(32) . f(2) = f(0.5)^5 . f(2)^10 . f(0.5) . f(2)^2 = f(0.5)^6 . f(2)^12
8. f(128) = f(64 . 2) = f(64) . f(2) = f(0.5)^6 . f(2)^12 . f(0.5) . f(2)^2 = f(0.5)^7 . f(2)^14 = 4
Substituting f(128) = 4 into the expression for M, we get:
M = f(0.5) . f(1) . f(2) . f(4) . f(8) . f(16) . f(32)
|
Explore Courses for Quant exam
|
|
Similar Quant Doubts
A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer?
Question Description
A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer?.
A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer?.
Solutions for A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Quant.
Download more important topics, notes, lectures and mock test series for Quant Exam by signing up for free.
Here you can find the meaning of A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A certain function always obeys the rule: If f (x.y) = f(x). f(y) where x and y are positive realnumbers. A certain Mr. Mogambo found that the value of f (128) = 4, then find the value of thevariable M = f (0.5). f (1). f (2). f (4). f (8). f (16). f (32). f (64). f (128). f (256)a)128b)256c)512d)1024Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Quant tests.
|
|
Explore Courses for Quant exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup