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A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps andone leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by thedog (assume an open field with no trees)
- a)12 minutes
- b)15 minutes
- c)12.5 minutes
- d)None of these
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A dog sees a cat. It estimates that the cat is 25 leaps away. The cat ...
Initial distance = 25 dog leaps.
Per minute Æ dog makes 5 dog leaps
Per minute Æ Cat makes 6 cat leaps = 3 dog leaps.
Relative speed = 2 dog leaps/minutes.
An initial distance of 25 dog leaps would get covered in 12.5 minutes.
Per minute Æ dog makes 5 dog leaps
Per minute Æ Cat makes 6 cat leaps = 3 dog leaps.
Relative speed = 2 dog leaps/minutes.
An initial distance of 25 dog leaps would get covered in 12.5 minutes.
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A dog sees a cat. It estimates that the cat is 25 leaps away. The cat ...
Problem Statement:
A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps and one leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by the dog (assume an open field with no trees).
Solution:
Given, the dog makes 5 leaps per minute and the cat makes 6 leaps per minute. Also, one leap of the dog is equal to 2 leaps of the cat. Let's assume the time taken by the dog to catch the cat is 't' minutes.
Distance covered by the cat in 't' minutes = 6t leaps.
Distance covered by the dog in 't' minutes = 5t*2 = 10t leaps.
When the dog catches the cat, both of them would have covered the same distance. Therefore, we can equate the distances and solve for 't'.
6t = 25 + 10t
4t = 25
t = 6.25 minutes
But we need to consider the time taken for the dog to start chasing the cat after estimating the distance. Let's assume this time as 'x' minutes.
Distance covered by the cat in 'x' minutes = 6x leaps.
Distance covered by the dog in 'x' minutes = 5x*2 = 10x leaps.
When the dog starts chasing the cat, the distance between them is 25 leaps. Therefore, we can equate the distances and solve for 'x'.
25 + 6x = 10x
4x = 25
x = 6.25 minutes
The total time taken by the dog to catch the cat is 'x + t' minutes.
Total time taken = 6.25 + 6.25 = 12.5 minutes.
Hence, the correct answer is option 'C'.
A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps and one leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by the dog (assume an open field with no trees).
Solution:
Given, the dog makes 5 leaps per minute and the cat makes 6 leaps per minute. Also, one leap of the dog is equal to 2 leaps of the cat. Let's assume the time taken by the dog to catch the cat is 't' minutes.
Distance covered by the cat in 't' minutes = 6t leaps.
Distance covered by the dog in 't' minutes = 5t*2 = 10t leaps.
When the dog catches the cat, both of them would have covered the same distance. Therefore, we can equate the distances and solve for 't'.
6t = 25 + 10t
4t = 25
t = 6.25 minutes
But we need to consider the time taken for the dog to start chasing the cat after estimating the distance. Let's assume this time as 'x' minutes.
Distance covered by the cat in 'x' minutes = 6x leaps.
Distance covered by the dog in 'x' minutes = 5x*2 = 10x leaps.
When the dog starts chasing the cat, the distance between them is 25 leaps. Therefore, we can equate the distances and solve for 'x'.
25 + 6x = 10x
4x = 25
x = 6.25 minutes
The total time taken by the dog to catch the cat is 'x + t' minutes.
Total time taken = 6.25 + 6.25 = 12.5 minutes.
Hence, the correct answer is option 'C'.
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A dog sees a cat. It estimates that the cat is 25 leaps away. The cat ...
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A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps andone leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by thedog (assume an open field with no trees)a)12 minutesb)15 minutesc)12.5 minutesd)None of theseCorrect answer is option 'C'. Can you explain this answer?
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A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps andone leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by thedog (assume an open field with no trees)a)12 minutesb)15 minutesc)12.5 minutesd)None of theseCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps andone leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by thedog (assume an open field with no trees)a)12 minutesb)15 minutesc)12.5 minutesd)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps andone leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by thedog (assume an open field with no trees)a)12 minutesb)15 minutesc)12.5 minutesd)None of theseCorrect answer is option 'C'. Can you explain this answer?.
A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps andone leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by thedog (assume an open field with no trees)a)12 minutesb)15 minutesc)12.5 minutesd)None of theseCorrect answer is option 'C'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps andone leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by thedog (assume an open field with no trees)a)12 minutesb)15 minutesc)12.5 minutesd)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dog sees a cat. It estimates that the cat is 25 leaps away. The cat sees the dog and starts running with the dog in hot pursuit. If in every minute, the dog makes 5 leaps and the cat makes 6 leaps andone leap of the dog is equal to 2 leaps of the cat. Find the time in which the cat is caught by thedog (assume an open field with no trees)a)12 minutesb)15 minutesc)12.5 minutesd)None of theseCorrect answer is option 'C'. Can you explain this answer?.
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