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Walking at 3/4 of his normal speed, a man takes 2(1/2) hours more than the normal time. Find thenormal time.
- a)7.5 h
- b)6 h
- c)8 h
- d)12 h
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Walking at 3/4 of his normal speed, a man takes 2(1/2) hours more than...
When his speed becomes 3/4th, his time would increase by 1/3rd. Thus, the normal time = 7.5 hrs.
(since increased time = 2.5 hrs).
(since increased time = 2.5 hrs).
Most Upvoted Answer
Walking at 3/4 of his normal speed, a man takes 2(1/2) hours more than...
Given:
- Walking at 3/4 of his normal speed
- Takes 2(1/2) hours more than the normal time
To find:
- Normal time
Solution:
Let's assume that the normal speed of the man is 'S' and the distance he travels is 'D'
- Normal time taken to travel the distance 'D' = D/S
- Time taken to travel the same distance at 3/4th of his speed = D/(3S/4) = 4D/3S
According to the question, the time taken at 3/4th of his speed is 2(1/2) hours more than the normal time. So we can form an equation as follows:
4D/3S = D/S + 2(1/2)
Solving the above equation, we get:
D = 15S
Substituting D = 15S in D/S, we get:
Normal time = 15 hours / S
Therefore, the correct option is (a) 7.5 hours.
- Walking at 3/4 of his normal speed
- Takes 2(1/2) hours more than the normal time
To find:
- Normal time
Solution:
Let's assume that the normal speed of the man is 'S' and the distance he travels is 'D'
- Normal time taken to travel the distance 'D' = D/S
- Time taken to travel the same distance at 3/4th of his speed = D/(3S/4) = 4D/3S
According to the question, the time taken at 3/4th of his speed is 2(1/2) hours more than the normal time. So we can form an equation as follows:
4D/3S = D/S + 2(1/2)
Solving the above equation, we get:
D = 15S
Substituting D = 15S in D/S, we get:
Normal time = 15 hours / S
Therefore, the correct option is (a) 7.5 hours.
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Walking at 3/4 of his normal speed, a man takes 2(1/2) hours more than the normal time. Find thenormal time.a)7.5 hb)6 hc)8 hd)12 hCorrect answer is option 'A'. Can you explain this answer?
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