There are two pipes in a tank. Pipe A is for filling the tank and Pipe...
A’s work = 10%
B’s negative work = 6.66%
(A + B)’s work = 3.33%
To fill a half empty tank, they would take 50/3.33 = 15 hours.
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There are two pipes in a tank. Pipe A is for filling the tank and Pipe...
Let's assume the capacity of the tank is 'x'.
So, initially, the tank is half-filled. Therefore, the quantity of water in the tank is x/2.
Let's consider the time taken by both pipes to fill or empty the tank as 't' hours.
Amount of water filled by Pipe A in 1 hour = x/10
Amount of water emptied by Pipe B in 1 hour = x/15
Now, let's calculate the net amount of water filled in the tank in 1 hour.
Net amount of water filled in the tank in 1 hour = (x/10) - (x/15)
= (3x - 2x)/30
= x/30
Therefore, Pipe A can fill x/30 amount of water in the tank in 1 hour.
Now, let's calculate the time taken to completely fill the half-empty tank.
Amount of water to be filled in the tank = x - x/2
= x/2
Time taken to fill the half-empty tank = (x/2) / (x/30)
= 15 hours
Therefore, it will take 15 hours to completely fill the half-empty tank. Hence, option (b) is the correct answer.
There are two pipes in a tank. Pipe A is for filling the tank and Pipe...
A Tank is filled with the mixture of Milk and Water in the ratio of 3:2 up to 2/5 of its capacity. The tank has two inlet pipes ie., Milk and Water inlets. Milk and Water pipe can fill an empty tank in 12 and 18 hours respectively. Now both pipes are opened simultaneously and closed after the Tank is completely filled, then what is the ratio of Milk and Water in the full Tank if it can accommodate 250Litre?