A vessel contains a mixture of two liquids A and B in the ratio of 7:5...
Let 7x and 5x volume of liquids A and Liquid B are present in vessel then,
Hence, 7.3 = 211 liquid A was present.
View all questions of this test
A vessel contains a mixture of two liquids A and B in the ratio of 7:5...
Given:
- Initially, the ratio of A and B in the mixture = 7:5
- 9 litres of the mixture is taken out and replaced with B
- After the replacement, the ratio of A and B in the mixture = 7:9
To Find: The initial quantity of liquid A in the vessel
Solution:
Let's assume that the initial quantity of the mixture in the vessel is 12x litres (7x litres of liquid A and 5x litres of liquid B).
Step 1: Calculation before replacement
- Initially, A:B = 7:5, so the quantity of A and B in the mixture would be 7x and 5x respectively.
- Therefore, the total quantity of the mixture in the vessel = 7x + 5x = 12x litres
Step 2: Calculation after replacement
- 9 litres of the mixture is taken out, so the quantity of the mixture left in the vessel = 12x - 9 litres
- This quantity is then filled with B. Let's assume that y litres of B is added to the mixture to fill the vessel
- Now, the quantity of B in the mixture = 5x + y litres, and the quantity of A in the mixture = 7x litres
- As per the question, the ratio of A and B in the mixture after replacement = 7:9, so we can form an equation as follows:
7x/(5x+y) = 7/9
- Cross-multiplying, we get:
63x = 35x + 9y
- Simplifying, we get:
28x = 9y
Step 3: Solving the equations
- We have two equations now:
12x - 9 = 5x + y (from step 2)
28x = 9y (from step 2)
- Solving these equations simultaneously, we get:
x = 3, y = 28
- Therefore, the initial quantity of liquid A in the vessel = 7x = 21 litres
Final Answer: The initial quantity of liquid A in the vessel was 21 litres. Hence, option (b) is the correct answer.