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The average of 10 two-digit positive integers is Z. However, one number AB is taken as BA, then the average increases to Z + 2.7. What is the value of |B - A|?
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'C'. Can you explain this answer?
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The average of 10 two-digit positive integers is Z. However, one numbe...
Given:
- Average of 10 two-digit positive integers = Z
- Average increases to Z+2.7 when one number AB is taken as BA

To find: |B - A|

Solution:
Let's assume that the sum of original 10 two-digit positive integers is S.
So, we can say that:
- Average of 10 two-digit positive integers = S/10 = Z
- Sum of 10 two-digit positive integers = S

When we interchange the digits of one number AB and make it BA, the sum of the 10 two-digit positive integers will increase by (BA - AB) = 9(B - A).
So, the sum of the 10 two-digit positive integers after this interchange will be (S + 9(B - A)).

Now, we know that:
- Average of 10 two-digit positive integers after the interchange = (S + 9(B - A))/10 = Z + 2.7

Substituting the value of Z from the first equation, we get:
(S + 9(B - A))/10 = (S/10) + 2.7

Simplifying this equation, we get:
9(B - A) = 27
B - A = 3

Therefore, the value of |B - A| is 3, which is option (c).

Hence, option (c) is the correct answer.
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