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In CE configuration, if the voltage drop across 5kΩ resistor connected in the collector circuit is 5V. Find the value of IB when β=50.
- a)0.01mA
- b)0.25mA
- c)0.03mA
- d)0.02mA
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
In CE configuration, if the voltage drop across 5kΩ resistor con...
IC=V across RL/RL=5V/5KΩ=1mA.
IB=IC/β=1/50=0.02mA.
IB=IC/β=1/50=0.02mA.
Most Upvoted Answer
In CE configuration, if the voltage drop across 5kΩ resistor con...
The transistor is in active mode and the current gain (β) is 100.
We can use the following formula to find the value of IB:
IB = (IC / β)
We know that in active mode, the collector current (IC) is given by:
IC = (VCC - VCE) / RC
Here, VCC is the supply voltage, VCE is the voltage drop across the collector-emitter junction, and RC is the resistance of the collector resistor.
From the given information, we know that VCE is equal to 5V and RC is equal to 5kΩ. Assuming that VCC is large enough to ensure that the transistor is in active mode, we can use VCC = 10V for simplicity.
Substituting these values in the above formula, we get:
IC = (10V - 5V) / 5kΩ
IC = 1mA
Now, using the formula for IB, we get:
IB = (1mA / 100)
IB = 10μA
Therefore, the value of IB when the transistor is in active mode and the current gain (β) is 100 is 10μA.
We can use the following formula to find the value of IB:
IB = (IC / β)
We know that in active mode, the collector current (IC) is given by:
IC = (VCC - VCE) / RC
Here, VCC is the supply voltage, VCE is the voltage drop across the collector-emitter junction, and RC is the resistance of the collector resistor.
From the given information, we know that VCE is equal to 5V and RC is equal to 5kΩ. Assuming that VCC is large enough to ensure that the transistor is in active mode, we can use VCC = 10V for simplicity.
Substituting these values in the above formula, we get:
IC = (10V - 5V) / 5kΩ
IC = 1mA
Now, using the formula for IB, we get:
IB = (1mA / 100)
IB = 10μA
Therefore, the value of IB when the transistor is in active mode and the current gain (β) is 100 is 10μA.
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In CE configuration, if the voltage drop across 5kΩ resistor connected in the collector circuit is 5V. Find the value of IBwhen β=50.a)0.01mAb)0.25mAc)0.03mAd)0.02mACorrect answer is option 'D'. Can you explain this answer?
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In CE configuration, if the voltage drop across 5kΩ resistor connected in the collector circuit is 5V. Find the value of IBwhen β=50.a)0.01mAb)0.25mAc)0.03mAd)0.02mACorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about In CE configuration, if the voltage drop across 5kΩ resistor connected in the collector circuit is 5V. Find the value of IBwhen β=50.a)0.01mAb)0.25mAc)0.03mAd)0.02mACorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In CE configuration, if the voltage drop across 5kΩ resistor connected in the collector circuit is 5V. Find the value of IBwhen β=50.a)0.01mAb)0.25mAc)0.03mAd)0.02mACorrect answer is option 'D'. Can you explain this answer?.
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