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A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.?
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A 100-ohm resistor is connected to the secondary of an ideal transform...
Problem:
A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.
Solution:
Step 1: Find the primary voltage
The voltage across the primary is given by the turns ratio of the transformer. Since the turns ratio is 1:4, the primary voltage is:
Vp = Vs × Np / Ns
= 10 V × 1 / 4
= 2.5 V
Step 2: Find the primary current
The primary current can be found using Ohm's Law. The resistance of the primary circuit is:
Rp = (Np / Ns)^2 × Rs
= (1 / 4)^2 × 100 ohm
= 6.25 ohm
Therefore, the primary current is:
Ip = Vp / Rp
= 2.5 V / 6.25 ohm
= 0.4 A
Step 3: Find the voltage across the secondary
The voltage across the secondary can be found using the turns ratio of the transformer. Since the turns ratio is 1:4, the secondary voltage is:
Vs = Vp × Ns / Np
= 2.5 V × 4 / 1
= 10 V
Step 4: Find the voltage across the 100-ohm resistor
The voltage across the 100-ohm resistor can be found using Ohm's Law. Since the resistor is connected to the secondary, the voltage across it is:
Vr = Is × Rs
= Vs / Ns × Rs
= 10 V / 4 × 100 ohm
= 0.025 V
Therefore, the voltage across the 100-ohm resistor is 0.025 V.
Conclusion:
The voltage across the 100-ohm resistor is 0.025 V and the primary current is 0.4 A.
A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.
Solution:
Step 1: Find the primary voltage
The voltage across the primary is given by the turns ratio of the transformer. Since the turns ratio is 1:4, the primary voltage is:
Vp = Vs × Np / Ns
= 10 V × 1 / 4
= 2.5 V
Step 2: Find the primary current
The primary current can be found using Ohm's Law. The resistance of the primary circuit is:
Rp = (Np / Ns)^2 × Rs
= (1 / 4)^2 × 100 ohm
= 6.25 ohm
Therefore, the primary current is:
Ip = Vp / Rp
= 2.5 V / 6.25 ohm
= 0.4 A
Step 3: Find the voltage across the secondary
The voltage across the secondary can be found using the turns ratio of the transformer. Since the turns ratio is 1:4, the secondary voltage is:
Vs = Vp × Ns / Np
= 2.5 V × 4 / 1
= 10 V
Step 4: Find the voltage across the 100-ohm resistor
The voltage across the 100-ohm resistor can be found using Ohm's Law. Since the resistor is connected to the secondary, the voltage across it is:
Vr = Is × Rs
= Vs / Ns × Rs
= 10 V / 4 × 100 ohm
= 0.025 V
Therefore, the voltage across the 100-ohm resistor is 0.025 V.
Conclusion:
The voltage across the 100-ohm resistor is 0.025 V and the primary current is 0.4 A.
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A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.?
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A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.?.
A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4. A 10 V RMS, 1 kHz voltage source is connected to the primary. Find the voltage across the 100-ohm resistor and the primary current.?.
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