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If a^2 b^2 c^2=14, then ab BC ca is always greater than or equal to- (1)0. (2)14. (3) -1. (4) -7. Explain.?
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If a^2 b^2 c^2=14, then ab BC ca is always greater than or equal to...
A² + b² + c² = 14


In this situation we are aware of the fact that the square of every number is greater than or equal to 0.


now we will take the square of (a+b+c)


=} (a+b+c)²≥ 0


=} a² + b² + c²  + 2(ab + bc + ca) ≥ 0


=} 14 +2 (ab + bc + ca) ≥ 0


=} 2 (ab + bc + ca) ≥ - 14


=} ab  + bc + ca ≥ -14/2


=} ab + bc + ca ≥ - 7


If there is any confusion please leave a comment below.

That's all🙂
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If a^2 b^2 c^2=14, then ab BC ca is always greater than or equal to- (1)0. (2)14. (3) -1. (4) -7. Explain.?
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