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The collector supply voltage for a CE configured transistor is 10V. The resistance RL=800Ω. The voltage drop across RL is 0.8V. Find the value of collector emitter voltage.
  • a)
    3.7V
  • b)
    9.2V
  • c)
    6.5V
  • d)
    9.8V
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The collector supply voltage for a CE configured transistor is 10V. Th...
Here, IC=0.8/800=1mA.
We know, VCE=VCC-ICRL
=10-0.8=9.2V.
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Most Upvoted Answer
The collector supply voltage for a CE configured transistor is 10V. Th...
Given data:
Collector supply voltage, Vcc = 10V
Load resistance, RL = 800Ω
Voltage drop across RL, VRL = 0.8V

To find: Collector-emitter voltage, VCE

Solution:
The voltage drop across the transistor in CE configuration is given by:
VCE = Vcc - VRL
Substituting the given values, we get:
VCE = 10V - 0.8V
VCE = 9.2V

Therefore, the value of collector-emitter voltage is 9.2V.

Answer: Option B (9.2V)
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The collector supply voltage for a CE configured transistor is 10V. The resistance RL=800Ω. The voltage drop across RLis 0.8V. Find the value of collector emitter voltage.a)3.7Vb)9.2Vc)6.5Vd)9.8VCorrect answer is option 'B'. Can you explain this answer?
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